 | Oliver Welch - 1812 - 236 páginas
...to measure whteh.. measure the sector ABCD by case 11, and also meus 02 r ure the triangle ADC, and subtract the area of the triangle from the area of the sector ; and the remainder will be tiie area of the segment AB C. \ Examples. » \. What is the area of the... | |
 | Thomas Keith - 1817 - 306 páginas
...as the segment. (Problem XV.) Kind the area of the triangK', formed by the chord of the segment and the radii of the sector. Then, if the segment be less than a semicircle, the difference of these two ar;'as will give the answer; but if the segment be greater lhan a semicircle,... | |
 | William Hawney - 1820 - 336 páginas
...whole sector CADBC by Section XII. and then (by Section V.) find the area of the triangle ABC, and subtract the area of the triangle from the area of the sector, the remainder will be the area of the segment. If the segment be greater than a semicircle, add the... | |
 | Beriah Stevens - 1822 - 436 páginas
...and perpendicular height 34, found by subtracting the versed sine BD from half the diameter ; then subtract the area of the triangle from the area of the sector, and the remainder will be the area of the segment ABC. See the work. 104=BC B 2 208 172= 12 208 add.... | |
 | Jeremiah Day - 1824 - 440 páginas
...ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, w THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT THE...AREA OF THE TRIANGLE FROM THE AREA OF THE SECTOR. BlJT, IF THE SEGMENT BE GREATER THAN A SEMI-CIRCLE, ADD THE AREA OF THE TRIANGLE TO THE AREA OF THE... | |
 | James L. Connolly (mathematician.) - 1829 - 266 páginas
...and multiply the half chord by the perpendicular, and the product is the area of the triangle. Then subtract the area of the triangle from the area of the sector, and the remainder is the area of the segment. Let it be required to find the area of the segment of... | |
 | Jeremiah Day - 1831 - 520 páginas
...SECTOR WHICH HAS THE SAME ARC, AND ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, IF THE SEGMENT BE LESS...AREA OF THE TRIANGLE FROM THE AREA OF THE SECTOR. BlJT, IF THE SEGMENT BE GREATER THAN A SEMI-CIRCLE, ADD THE AREA OF THE TRIANGLE TO THE AREA OF THE... | |
 | James L. Connolly (mathematician.) - 1835 - 264 páginas
...and multiply the half chord by the perpendicular, and the product is the area of the triangle. Then subtract the area of the triangle from the area of the sector, and the remainder is the area of the segment. Let it be required to find the area of the segment of... | |
 | Jeremiah Day - 1836 - 418 páginas
...AND ALSO THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEOMENT AND THE RADII OF THE SECTOR. I THEN, IF THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT...the sector AOBC, it is evident the difference will he the segment AOBP, less than a semi-circle. And if the same triangle be added to the sector ADBC,... | |
 | 1836 - 488 páginas
...sector which has the same arc, and also the area of the triangle formed by the chord of the segment, and the radii of the sector. Then, if the segment be less...be greater than a semicircle, add the area of the trian, gle to the area of the sector. To find the area of a circular zone. From the area of the whole... | |
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THE AREA OF THE TRIANGLE FORMED BY THE CHORD OF THE SEGMENT AND THE RADII OF THE SECTOR. THEN, IF THE SEGMENT BE LESS THAN A SEMI-CIRCLE, SUBTRACT THE AREA OF THE TRIANGLE FROM THE AREA OF THE SECTOR. 
