CHAPTER X.

ON THE TRAVERSE TABLE.

HAVING in the last few Chapters given an explanation of the Traverse System of surveying from its commencement, viz. : the angular work and measurements in the field, to the finding the area of the land surveyed, it only remains to simplify the process, which has taken some pages for explanation, by embodying the whole in a table for the purpose and calculating the polygon given in page (295). In the adjoining table

10

11

12

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Survey.

the angles as observed in the Field.

the corrections made in those angles, to prove

them by Cor. 3, Theo. V., Page 12.

the bearings of the several lines deduced as per Rule Page 277.

the distances as measured in the Field.

the distance on the meridian between every two stations.

the departure of each station from the meridian
of the preceding one.

the corrections applied to each calculation, to
prove the Survey correct
Page 284.

as per Rule

the distances on the meridian of each station

from the first in the series.

the departure of each station from the first in

the series.

the sums of each pair of co-ordinates obtained from Column 11, to be multiplied into Columns 6 and 7, when the respective products are placed in Columns 13 and 14.

10

11

Correction.

South.

+ Correction.

East.

+ Correction.

West.

12

13

14

Correction.

Distances on the meridian of each station from the first station in Distances on the perpendicular or departure of each station from the first station in the series. Sums of the distances on the perpendicular as co-ordinates for multithe series.

pliers.

North Products in Acres.

South Products in Acres.

Chs. Lks. Chs. Lks.

Chs. Lks.+Chs. Lks. + Chs.Lks.

Chs.Lks. Chs. Lks. Chs. Lks. NE & SW NW & SE

The following simplification of the method of calculating columns 4, 6, 7, 8, 9, 10, 11, 12, 13 and 14 will, it is hoped, place the matter beyond doubt; and by comparing each given quantity with the diagrams, the mode of obtaining its corresponding result will be easily understood.

To obtain Column 4 of the Table from Column 2.

Given the Bearing of the line AB, 50° 12′ N. E. as found by Astronomical observation, or otherwise. (Diagram Page 278.) Then,

Bearg. AB 50° 12′ + B270° 11′=320° 23′-180°-140° 23′ S. E. or Bearg. BC
BC 140 23,, C 61 10-201 33-180 = 21 33 N. E.
CD 21 33 + D 113 41-135 14+180 315

CD

14 N. W.

DE

To obtain Columns 6, 7, 8 and 9.

Rule. As Radius: Distance:: Cosine of Bearing: Latitude

and :: Sine of Bearing: Longitude or Departure.

Example of Columns 6, 7, 8 and 9.

On the Line AB given, Bearing N. E. 50° 12' Distance 8.35

The above example by Major Boileau's Tables, (see Note Page 289.)

To obtain Column 10 from Columns 6 and 7.

To obtain Column 11 from Columns 8 and 9.

Line AB Departure of A to B or bB:

E 6.42

To obtain Column 12 from Column 11.

Line AB Departure of A to B or bB E 6·42