 | Benjamin Greenleaf - 1863 - 338 páginas
...trial divisor, three times the product of the first term by the last, and the square of the last, for a complete divisor. Multiply the complete divisor by the last term of the root, and subtract the product from the dividend. If there are other terms remaining, form a new dividend,... | |
 | William Guy Peck - 1875 - 348 páginas
...add the quotient to the root found, and also to the divisor; multiply the divisor, thus augmented, by the last term of the root found, and subtract the product from the first remainder for a second remainder. III. Double the root already found for a second divisor. Divide... | |
 | Edward Brooks - 1876 - 584 páginas
...the trial divisor for a CORRECTION; add the CORRECTION to the TRIAL DIVISOR, and the result will be the COMPLETE DIVISOR ; multiply the COMPLETE DIVISOR by the last term of the root, subtract the product from the dividend, and annex the next period to the result for a new dividend.... | |
 | Edward Brooks - 1877 - 528 páginas
...the trial divisor for a CORRECTION ; add the CORRECTION to the TRIAL DIVISOR, and the result will be the COMPLETE DIVISOR ; multiply the COMPLETE DIVISOR by the last term of the root, subtract the product from the dividend, and annex the next period to the result for a new dividend.... | |
 | Edward Brooks - 1877 - 232 páginas
...the trial divisor for a CORRECTION ; add the CORREC TION to the TRIAL DIVISOR, and the result will be the COMPLETE DIVISOR ; multiply the COMPLETE DIVISOR by the last term of the root, subtract the product from the dividend, and annex the next period to the result for a new dividend.... | |
 | Edward Brooks - 1877 - 444 páginas
...trial divisor for a CORRECTION ; add the CORRK« riON to the TRIAL DIVISOR, and the result will be the COMPLETE DIVISOR; multiply the COMPLETE DIVISOR by the last term of the root, subtract the product from the dividend, and annex the next period to the result for a new dividend.... | |
 | Benjamin Greenleaf - 1879 - 322 páginas
...divisor, three times the product of the first term by the second, and the square of the second, for a complete divisor. Multiply the complete divisor by the last term of the root, and subtract the product from the remainder. If there are other terms remaining, continue the operation... | |
 | Edward Albert Bowser - 1888 - 868 páginas
...this trial divisor for the second term of the root, and annex this second term to the root and also to the trial divisor for the complete divisor. Multiply the complete divisor by the second term of the root, and subtract the product from the remainder. If there are other terms remaining,... | |
 | Edward Brooks - 1888 - 344 páginas
...1« EVOLUT1IAN. for a CORRECTION ; add the CORRECTION to iAe TRIAL DFVIBOK, and the reau.ll will Ьк the COMPLETE DIVISOR; multiply the COMPLETE DIVISOR by the last term of the root, subtract the prothiet from the dividend, and annex the next period to the result for a new dividend.... | |
 | Charles Davies - 1889 - 330 páginas
...add the quotient to the root found, and also to the divisor; multiply the divisor, thus augmented, by the last term of the root found, and subtract the product from the first remainder for a second remainder. ID. Double the root already found for a second divisor. Divide... | |
| |
Tlie result will be the complete divisor. Multiply the complete divisor by the last term of the root found, and subtract this product from the dividend. 
