Elementary Trigonometry: With a Collection of ExamplesDeighton, Bell, and Company, 1862 - 184 páginas |
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Página 88
... radii of the inscribed and escribed circles . 3. Lengths of tangents to the inscribed and escribed circles from the angles of a triangle . If the inscribed circle touches the triangle in the points a , b , c , since tangents drawn to a ...
... radii of the inscribed and escribed circles . 3. Lengths of tangents to the inscribed and escribed circles from the angles of a triangle . If the inscribed circle touches the triangle in the points a , b , c , since tangents drawn to a ...
Página 92
... radii of these two circles . Let O be the centre of the inscribed , and O of the cir- cumscribed circle . B O ' N K A - A , because Then O'B = R , OK = r , O'BC = 90 ° BO'N = A , it being half the angle at the centre , which is 24 . B ...
... radii of these two circles . Let O be the centre of the inscribed , and O of the cir- cumscribed circle . B O ' N K A - A , because Then O'B = R , OK = r , O'BC = 90 ° BO'N = A , it being half the angle at the centre , which is 24 . B ...
Página 115
... radii of the wheels . Ans . The ratio is 180 : π . EXAMPLES ILLUSTRATING CHAPTER ' II . a 1. Given tan 0 = find sin and cos 0 . b ' sin 0 α - tan 0 : = COS ... sin bears the same ratio to a that cos 0 bears to b . Let this ratio be λ ...
... radii of the wheels . Ans . The ratio is 180 : π . EXAMPLES ILLUSTRATING CHAPTER ' II . a 1. Given tan 0 = find sin and cos 0 . b ' sin 0 α - tan 0 : = COS ... sin bears the same ratio to a that cos 0 bears to b . Let this ratio be λ ...
Página 160
... radii of the escribed circles are in arithmetic progression . · solve Ans , B = 45 ° . 41. In any triangle ABC , given A = 60o , a = √√6 , b = 2 , the triangle . 42. Given A = 30o , a = √√√2 , b = 2 , solve the triangle . 43. Given ...
... radii of the escribed circles are in arithmetic progression . · solve Ans , B = 45 ° . 41. In any triangle ABC , given A = 60o , a = √√6 , b = 2 , the triangle . 42. Given A = 30o , a = √√√2 , b = 2 , solve the triangle . 43. Given ...
Página 166
... radii of the inscribed and escribed circles of a triangle , then ra + rb + rc¬r = 4R . If A the area of the triangle = ra + rb + rc - r = A I I I - ( ++ ) ( Ch . x . Art . 2 ) ق ) - A 8- 8 - C s ( s − a ) ( s — b ) ( s −c ) I ...
... radii of the inscribed and escribed circles of a triangle , then ra + rb + rc¬r = 4R . If A the area of the triangle = ra + rb + rc - r = A I I I - ( ++ ) ( Ch . x . Art . 2 ) ق ) - A 8- 8 - C s ( s − a ) ( s — b ) ( s −c ) I ...
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Términos y frases comunes
a+b+c a²+b² angle AOP angle of elevation angular arithmetical progression B-sin bisecting centre circular measure circumference circumscribing circle cos² cos³ cosec cosine cubic equation decimal decreases in magnitude determined distance equal escribed circles EXAMPLES ILLUSTRATING CHAPTER feet Find the number find the value formula Given log given value Hence horizontal plane increases inscribed integer logarithm mount Ebal number of degrees number of grades Observe the angles perpendicular polygon Prove Quadrant quadrilateral radii radius regular polygon respectively revolving line right angle sec² secant secondary angle shew sides sign and magnitude similar triangles Similarly sin A sin sin² sin³ sine sines and cosines Solve the equation solve the triangle straight line subtend tan² tangent tower triangle ABC trigono trigonometrical functions versin π π
Pasajes populares
Página 64 - The logarithm of the product of two numbers is equal to the sum of the logarithms of the numbers.
Página 1 - A plane rectilineal angle is the inclination of two straight lines to one another, which meet together, but are not in the same straight line.
Página 175 - ... 66. Construct an equilateral triangle, having given the length of the perpendicular drawn from one of the angles on the opposite side. 67. Having given the straight lines which bisect the angles at the base of an equilateral triangle, determine a side of the triangle. 68. Having given two sides and an angle of a triangle, construct the triangle, distinguishing the different cases. 69. Having given the base of a triangle, the difference...
Página 37 - B + cos A . sin B tan(A + B)= ) , (- = — . --. v cos (A + B) cos A . cos B — sin A . sin B and dividing numerator and denominator by cos A . cos B, sin A sin B cos A "'"cos B tan A + tan B 1 tan A.
Página 175 - Three circles are described, each of which touches one side of a triangle ABC, and the other two sides produced. If D be the point of contact of the side BC, E that of AC, and F that of AB, shew that AE is equal to BD, BF to CE, and CD to AF.
Página 5 - Now the angle at the centre of a circle which is subtended by an arc equal to the radius equals — = 57°. 29578, it so that the true length of a curve is given by the equation t IR L — ~ — — 57.2958 — 57.2958...
Página 113 - ... would be subtended at the centre of the first by an arc equal to the radius of the second. 9. If a be the arc which measures the complement of an angle to radius r, find the arc which measures the supplement of the same angle to radius r'.
Página 159 - It is required to bisect any triangle (1) bya line drawn parallel, (2) by a line drawn perpendicular, to the base. 43. To divide a given triangle into two parts, having a given ratio to one another, by a straight line drawn parallel to one of its...