 | John Playfair - 1806 - 320 páginas
...opposite angles, &c. Q. E, D. ^ PROP. XXIII. THEOR. Book in. UPON the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with each other. If it be possible, let the two similar segments of circles, ACB, ADB be upon the same side of the same... | |
 | Robert Simson - 1806 - 546 páginas
...angles, Sec. QE I). *— y~* PROP. XXIII. THEOR. UPON the same straight line, and upon the same See N. side of it, there cannot be two similar segments of circles not coinciding with one another. If it be possible, let the two similar segments of circles, viz. ACB, ADB, be upon the... | |
 | Euclid - 1810 - 554 páginas
...opposite angles, &c. QED PROP. XXIII. THEOR. UPON the same straight line, and upon the same See Noteside of it, there cannot be two similar segments of circles, not coinciding with one another. If it be possible, let the two similar segments of circles, viz. ACB, ABD be upon the... | |
 | John Mason Good - 1813 - 714 páginas
...circle, are together equal to two right angles. Prop. XXIII. Theor. Upon the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with one another. Prop. XXIV. Tlieor. Similar segments of circles Upon equal straight lines, are equal to... | |
 | John Playfair - 1819 - 350 páginas
...angles. Therefore the opposite angles, &c. QED PROP. XXIII. THEOR. Upon the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with one another. If it be possible, let the two similar segments of circles, vie. ACB, ADB, be upon the... | |
 | Euclides - 1821 - 294 páginas
...absurd. C'or. Hence every equiangular triangle is equilateral ; vide, Elrington. PROP. 7. THEOR. i On the same right line and on the same side of it there cannot be two triangles formed whose conterminous sides are equal. If it be possible that there can, 1st, let the... | |
 | Peter Nicholson - 1825 - 1046 páginas
...Therefore, the opposite angles, &c. QED Propotition XXIll. Theorem. Upon the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with one another. If it be possible, let the two similar segments of circles, viz. ACB, ADB, be upon the... | |
 | Robert Simson - 1827 - 546 páginas
...Therefore, the ppposite angles, &c. QED PROP. XXIII. THEOR. (See N. Upon the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding 'with one another. If it be possible, upon the same straight line AB, and upon the same side of it, let there... | |
 | Euclid, Robert Simson - 1829 - 548 páginas
...angles. Therefore the opposite angles, &c. QED PROP. XXIII. THEOR. UPON the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with one another.* Ifitbe possible,letthe two similarsegments of circles, viz. ACB, ABD be upon the same... | |
 | Euclides - 1833 - 304 páginas
...whole, which is absurd. Cor. Hence every equiangular triangle is equilateral ; vide Elrington. PROP. 7, THEOR. On the same right line and on the same side of it, there cannot be two triangles formed whose conterminous sides are equal. If it be possible that there can, 1st. let the... | |
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Upon the same straight line, and upon the same side of it, there cannot be two similar segments of circles, not coinciding with one another. 
