6. The breadth and thickness of a beam are 3 ft. 3 in. and 2 ft, 4in.; find by duodecimals the length of a piece which contains 14 cubic feet. Ans. 1 feet. 7. Find the size of a cube whose solidity is equal to that of a parallelopipedon whose dimensions are 1 ft. 8 in., 2 ft. 8 in., 4 ft. 1 in. Ans. 2 ft. 4 in. 8. The three contiguous edges of a parallelopipedon are 8, 10, 12; find the lengths of three lines drawn from one corner to the middle points of the opposite faces. Ans. 11*180, 12°324, 13.601. 9. The length and breadth of a 56 lb. weight are 8 and 6 inches; find the height, allowing 2 lbs. for the handle which is sunk into the weight. Ans. 45 inches. THE PRISM. This solid is contained by rectangular planes, all parallel to the same straight line; the ends are equal rectilineal figures. XXV. To find the solidity of a prism. Multiply the area of the end by the length. T. M. 5 Ex. Find the solidity of a pentagonal prism whose length is 7 ft. 3 in.; the side of the pentagon being 3 ft. 6 in. I. Find the solidity of a prism whose length is 20 ft. 6 in.; the end being an equilateral triangle whose side is 14 ft. 10 in. Ans. 1953 076 feet. 2. Find the solidity of a triangular prism whose length is 12 ft. 9 in.; the sides of the end being 7 ft. 3 in., 8 ft. 4 in., 9 ft. 5 in. Ans. 370 211 feet. 3. Find the solidity of an hexagonal prism whose length is 10 ft. 10 in.; the side of the hexagon being 5 ft. 5 in. Ans. 825 782 feet. 4. Find the solidity of a triangular prism whose length is 6 feet; the sides of the triangle being 2 ft. 1 in., 3 ft. 3 in., 4 ft. 8 in. Ans. 17 feet. THE CYLINDER. This solid is formed by the revolution of a rectangle about one of its sides. XXVI. To find the curve surface of a cylinder. Multiply the length by the diameter; then multiply by 3. Ex. Find the curve surface of a cylinder whose length is 10 ft. 3 in., and diameter 3 ft. 11 in. To find the solidity of a cylinder. Multiply the square of the diameter by the length; then multiply by 11 and divide by 14. Ex. Find the solidity of a cylinder whose length is 4 ft. 8 in., and diameter 2 ft. 6 in. CYLINDRICAL SHELL. XXVIII. To find the solidity of a cylindrical shell. Multiply the sum of the inner and outer diameters by their difference, and this product by the length of the shell; then multiply by 11 and divide by 14. Ex. Find the weight of a cast-iron pipe whose length is 9 feet, and the inner and outer diameters 6 and 8 inches. 8+6=14 8-6= 2 28 108 224 280 3024 3024 2 33264 7 16632 4 2376 594 Ans. 5 cwt. I qr. 6 lbs. |