 We may obtain the sixth root by extracting the cube root of the square root, or the square root of the cube root. It is, however, best to extract the roots of the lowest degrees first, because the operation is less laborious. We may obtain the eighth...  A Treatise on Algebra - Página 258por Elias Loomis - 1873 - 360 páginasVista completa - Acerca de este libro
 | Thomas Keith - 1822 - 354 páginas
...better methods. Thus, the square root of the square root=the biquadrate, or fourth rest, for £x|=«> The cube root of the square root, or the square root of the cube root «=*he sixth root, for |x!_s- The square root of the fourth root= the eighth root, for |xj=|, or £x$xi={-... | |
 | Thomas Keith - 1825 - 360 páginas
...better methods. Thus, the square root of the square rw>t=the biquadrate, or fourth root, for |xi=iThe cube root of the square root, or the square root of the cube root —the sixth root, for {x J=J. The square root of the fourth root= the eighth root, for ixj=|, or *x^X... | |
 | Frederick Emerson - 1834 - 300 páginas
...fourth power, and then the square root of that square root will be the fourth root. The sixth root is the cube root of the square root, or the square root of the cube root; because 3 X2 = 6. The eighth root is the square root of the square root of the square root; because... | |
 | Frederick Emerson - 1839 - 300 páginas
...fourth power, and then the square root of that square root will be the fourth root. The sixth root is the cube root of the square root, or the square root of the cube root; because 3 X2— 6. The eighth roct is the square root of the square root of the square root; because... | |
 | Roswell Chamberlain Smith - 1841 - 324 páginas
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root ; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ol the square root ; the ninth root (3x3)... | |
 | Roswell Chamberlain Smith - 1842 - 320 páginas
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root ; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ot the square root ; the ninth root (3x3)... | |
 | Roswell Chamberlain Smith - 1843 - 320 páginas
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ol the square root; the ninth root (3x3)... | |
 | James B. Dodd - 1850 - 278 páginas
...256 being thus equal to 4X4X4X 4, the 4th root of 256 is 4. In like manner, the 6th root is equal to the cube root of the square root, or the square root of the cube root ; and so on. Note. In common Arithmetic we seldom or never have occasion to employ any other than the... | |
 | Roswell Chamberlain Smith - 1850 - 314 páginas
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ot the square root ; the ninth root (3x3)... | |
 | James B. Dodd - 1852 - 410 páginas
...factors, and then such root of that root as is denoted by the other factor. The 6th root is equal to the cube root of the square root, or the square root of the cube root, — the fraction £, which is the exponent of the 6th root, being equal to | The 5th root cannot be... | |
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