...each side from that half sum ; then multiply the said half sum and the three remainders continually together ; and the square root of the product will be the area of the triangle. EXAMPLES. 1. — Required the area of the triangular field ABC, whose base AB is 650,...

...sides, subtract each side separately, and multiply the half sum and the three remainders continually together; and the square root of the product will be the area. the sides Then by hence AD r: — E 1C, geAC, and AB, t» — «' "~~ 2 с ¿> — ; o AD —DB = —...

...— c2) X (c2— a— 56 MENSURATION 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. EXAMPLES. 1. Required the area of the triangle ABC, whose three sides BC, CA, and AB are...

...three sides subtract each side severally. 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. RULE. ii. Any two sides of a triangle being multiplied together, and the product again by...

...subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root of the product will be the area of the triangle. Ex. 1. What is the area of a triangle whose base is 15 feet, and perpendicular height...

...sides subtract each side several! y, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. AN EXAMPLE. In the triangle ABC let the side AC be 40 poles, CB50, and AB 60 ; required,...

...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans....

...sum, subtract each side severally; from the half sum multiply the half sum and the three differences together, and the square root of the product will be the area. 1. Required the area of a right angled triangle whose base is 40 and perpendicular 30 perches? Ans....

...crooked fence, so as to include as much on one side as they exclude on the other. remainders continually together, and the square root of the product will be the area. EXAMPLES. I . Required the area of a triangle, the sides of which are 26, 28, and 30. 26 28 42 42 42...

...sides subtract each side severally, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. 1. What will be the area of the triangle AB c, the side of which, AB, is 50 ft., B c 40 ft.,...