Linear Drawing: Showing the Application of Practical Geometry to Trade and ManufacturesCassell, Petter, Galpin, & Company, 1869 - 118 páginas |
Dentro del libro
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Página iv
... equal in area to a given Polygon To construct a Triangle equal to a given Rectilineal Figure Ditto ditto ditto To divide a Triangle into two equal parts by a Line parallel to or perpendicular to one of its sides SQUARES . Definition of ...
... equal in area to a given Polygon To construct a Triangle equal to a given Rectilineal Figure Ditto ditto ditto To divide a Triangle into two equal parts by a Line parallel to or perpendicular to one of its sides SQUARES . Definition of ...
Página v
... equal in area to any given Polygon CIRCLES . FIG . PAGE -- 40 53 41 55 43 54 42 44 46 59 47 59 47 62 50 51 52 53 € 6 54 68 69 70 109 97 5555 55 56 57 57 To inscribe a Circle in any Triangle ... To draw a Circle passing through any three ...
... equal in area to any given Polygon CIRCLES . FIG . PAGE -- 40 53 41 55 43 54 42 44 46 59 47 59 47 62 50 51 52 53 € 6 54 68 69 70 109 97 5555 55 56 57 57 To inscribe a Circle in any Triangle ... To draw a Circle passing through any three ...
Página 17
... equal to A B C. On the given line A B , to construct a Triangle similar to C D E. ( Figs . 19 and 20. ) E A B N Fig ... area- that is , to contain precisely the same space . A figure may be equal to another without being similar in shape ...
... equal to A B C. On the given line A B , to construct a Triangle similar to C D E. ( Figs . 19 and 20. ) E A B N Fig ... area- that is , to contain precisely the same space . A figure may be equal to another without being similar in shape ...
Página 67
... same area . ( Fig . 80. ) C D E A 4 2 3 Fig . 80 . Draw a radius A B , and on it describe a semicircle . Divide the radius A B into the number of equal parts corresponding with the number of circles required . From the points of ...
... same area . ( Fig . 80. ) C D E A 4 2 3 Fig . 80 . Draw a radius A B , and on it describe a semicircle . Divide the radius A B into the number of equal parts corresponding with the number of circles required . From the points of ...
Página 68
... same area . The Cone and its Sections . ( Fig . 81. ) Fig . 81 . A Cone is a solid , the base of which is a circle , but which tapers to a point from the base upward . If a cone be cut horizontally — that is , parallel to the base - all ...
... same area . The Cone and its Sections . ( Fig . 81. ) Fig . 81 . A Cone is a solid , the base of which is a circle , but which tapers to a point from the base upward . If a cone be cut horizontally — that is , parallel to the base - all ...
Términos y frases comunes
A B and C D angle similar Bisect the angle bisecting line centre circle cutting complete the figure complete the square construct a Square construct a Triangle cutting C D cutting the circle cutting the lines cutting the perpendicular Cycloid describe a circle describe a semicircle describe an arc describe arcs cutting describe the arc diameters A B draw a line Draw E F draw lines drawn ellipse Epicycloid equal in area equilateral triangle erect a perpendicular F and G given circle given line H Draw heptagon Hypocycloid I J K intersecting Involute Isosceles Triangle Join these points length line A B line parallel number of equal octagon parallel to A B parallelogram polygon produce the bisecting quadrant radius A B radius O A rectangle regular Hexagon right angles straight line tangent Trapezium voussoirs wheel has moved
Pasajes populares
Página 101 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Página 17 - Most good practical workmen have several means for getting the cut of the mitre, and to them this demonstration will appear unnecessary, but I have seen many men make sad blunders, for want of knowing this simple rule. PROBLEM 12.
Página 43 - AB of the circle into as many equal parts as the polygon is to have sides. With the points A and B as centers and radius AB, describe arcs cutting each other at C.
Página 85 - The process is then continued from the inner squares. THE INVOLUTE (Fig. 61). If a perfectly flexible line is supposed to be wound round any curve, so as to coincide with it, and kept stretched as it is gradually unwound, the end of, or any point in the line will describe or trace another curve, called the involute of the curve — being in reality the opening out, or tmrolKnff, of the periphery of the first curved surface.
Página 12 - Set off these lengths on the pitch circle.* To construct an equilateral triangle on the given line AB (Fig. 5). From A, with radius AB, describe an arc. From B, with the same radius, describe a corresponding arc, cutting the former one in c. Lines joining A c and B c will complete the triangle, which will be equilateral, that is, all its sides will be equal. A triangle having only two of its sides equal, is called an isosceles triangle (A).