Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, a Treatise of the Nature and Arithmetic of Logarithms; Likewise Another of the Elements of Plane and Spherical Trigonometry; with a Preface, Shewing the Usefulness and Excellency of this WorkW. Strahan, 1772 - 399 páginas |
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Página 11
... Circle is a Right Lino drawn through the Centre , and terminated on both Sides by the Circumference , and divides the Circle into two equal Parts . XVIII . A Semicircle is a Figure contained under a Diameter , and that Part of the ...
... Circle is a Right Lino drawn through the Centre , and terminated on both Sides by the Circumference , and divides the Circle into two equal Parts . XVIII . A Semicircle is a Figure contained under a Diameter , and that Part of the ...
Página 11
... II . That a finite Right Line may be continued di- really forwards . III . And that a Circle may be defcribed about any Centre with any Distance . B 2 AXIOMS . AXIOM S. THINGS equal to one and the fame Thing Book I. Euclid's ELEMENTS . 3.
... II . That a finite Right Line may be continued di- really forwards . III . And that a Circle may be defcribed about any Centre with any Distance . B 2 AXIOMS . AXIOM S. THINGS equal to one and the fame Thing Book I. Euclid's ELEMENTS . 3.
Página 11
... Circle BCD * ; and about the Centre B , * Post . 3 . with the fame Diftance BA , defcribe the Circle ACE * ; and from the Point C , where the two Circles cut each other , draw the Right Lines CA , CB + . † Poft . I. Then because A is ...
... Circle BCD * ; and about the Centre B , * Post . 3 . with the fame Diftance BA , defcribe the Circle ACE * ; and from the Point C , where the two Circles cut each other , draw the Right Lines CA , CB + . † Poft . I. Then because A is ...
Página 11
... Circle BGH * ; and about the Centre D , with the Distance DG , defcribe the Circle K GL . Poft . 3 . Now because the Point C is the Centre of the Circle Def . 15. BGH , BC will be equal to CG + ; and because D is the Centre of the ...
... Circle BGH * ; and about the Centre D , with the Distance DG , defcribe the Circle K GL . Poft . 3 . Now because the Point C is the Centre of the Circle Def . 15. BGH , BC will be equal to CG + ; and because D is the Centre of the ...
Página 13
... Distance CD , defcribe a Circle E DG ; bifect + EG in H , P. 3 . t and join CG , CH , CE . I fay , there is drawn the † 10 of this . Per- Perpendicular CH on the given infinite Right Line AB , Book I. - Euclid's ELEMENTS . +3.
... Distance CD , defcribe a Circle E DG ; bifect + EG in H , P. 3 . t and join CG , CH , CE . I fay , there is drawn the † 10 of this . Per- Perpendicular CH on the given infinite Right Line AB , Book I. - Euclid's ELEMENTS . +3.
Otras ediciones - Ver todas
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2018 |
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2017 |
Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2015 |
Términos y frases comunes
A B C adjacent Angles alfo equal alſo Angle ABC Baſe becauſe bifected Centre Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs likewife Logarithm Magnitudes Meaſure Number oppofite parallel Parallelogram perpendicular Polygon Prifm Prop PROPOSITION Pyramid Quadrant Ratio Reafon Rectangle Rectangle contained remaining Angle Right Angles Right Line A B Right-lined Figure Segment ſhall Sides A B Sine Square Subtangent thefe THEOREM thofe thoſe tiple Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whoſe
Pasajes populares
Página 195 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Página 165 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Página 169 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles...
Página xxii - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Página 54 - If a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.
Página 123 - GB is equal to E, and HD to F; GB and HD together are equal to E and F together : wherefore as many magnitudes as...
Página 215 - CD; therefore AC is a parallelogram. In like manner, it may be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram...
Página 196 - ABC, and they are both in the same plane, which is impossible ; therefore the straight line BC is not above the plane in which are BD and BE: wherefore, the three straight lines BC, BD, BE are in one and the same plane. Therefore, if three straight lines, &c.
Página 161 - And because HE is parallel to KC, one of the sides of the triangle DKC, as CE to ED, so is...
Página 207 - A plane is perpendicular to a plane, when the straight lines drawn in one of the planes perpendicular to the common section of the two planes, are perpendicular to the other plane. V. The inclination of a straight line to a plane...