## Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, a Treatise of the Nature and Arithmetic of Logarithms; Likewise Another of the Elements of Plane and Spherical Trigonometry; with a Preface, Shewing the Usefulness and Excellency of this WorkW. Strahan, 1772 - 399 páginas |

### Dentro del libro

Resultados 1-5 de 82

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**firft**af fuming a certain Affection , agreeing only to one Kind of Proportionals , viz . Commenfu- rables ; and thence , by a long Circuit , and a perplexed Series of Conclufions , do deduce that univerfal Property of Proportionals ... Página 8

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**firft**fix , and the 11th and 12th . And as he found there was wanting a Treatife of these Parts of the Elements , as they were written by Euclid himself ; he he published his Edition without omitting any of Euclid's Demonftrations Mr ... Página 9

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**firft**of thefe , which was omitted , is here fupplied : And that which was cor- rupted is here restored * . And fince feveral Perfons , to whom the Elements of Geometry are of vast Use , either are not so fufficiently fkilled in , or ... Página 11

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**firft**to calculate that unknown Angle , before we shall know whether we are to take the Sum or the Difference of the vertical Angles or Bafes for the fought Angle or Bafe : And in the Calculation of that Angle have left us in the Dark ... Página 11

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**firft**Right Lines have , fo that CA be equal to AD , having the fame End A , which CA hath ; and CB equal to D B , having the fame End B. Cafe 1. The Point D cannot fall in the Line A C ; for inftance at F : For then ( AD that is ) A F ...### Otras ediciones - Ver todas

Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2018 |

Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2017 |

Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Sin vista previa disponible - 2015 |

### Términos y frases comunes

A B C adjacent Angles alfo equal alſo Angle ABC Baſe becauſe bifected Centre Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs likewife Logarithm Magnitudes Meaſure Number oppofite parallel Parallelogram perpendicular Polygon Prifm Prop PROPOSITION Pyramid Quadrant Ratio Reafon Rectangle Rectangle contained remaining Angle Right Angles Right Line A B Right-lined Figure Segment ſhall Sides A B Sine Square Subtangent thefe THEOREM thofe thoſe tiple Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whoſe

### Pasajes populares

Página 195 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Página 165 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.

Página 169 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles...

Página xxii - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...

Página 54 - If a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other part, is equal to the square of the straight line which is made up of the whole and that part.

Página 123 - GB is equal to E, and HD to F; GB and HD together are equal to E and F together : wherefore as many magnitudes as...

Página 215 - CD; therefore AC is a parallelogram. In like manner, it may be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram...

Página 196 - ABC, and they are both in the same plane, which is impossible ; therefore the straight line BC is not above the plane in which are BD and BE: wherefore, the three straight lines BC, BD, BE are in one and the same plane. Therefore, if three straight lines, &c.

Página 161 - And because HE is parallel to KC, one of the sides of the triangle DKC, as CE to ED, so is...

Página 207 - A plane is perpendicular to a plane, when the straight lines drawn in one of the planes perpendicular to the common section of the two planes, are perpendicular to the other plane. V. The inclination of a straight line to a plane...