A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes, Exercises and Explanations ... By C. Mansford1874 |
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Página 22
... angle BAC equal to the angle EDF , the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , B and the other angles shall be equal each to each , to which the equal sides are opposite , namely , the angle ...
... angle BAC equal to the angle EDF , the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , B and the other angles shall be equal each to each , to which the equal sides are opposite , namely , the angle ...
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... angle BAC coincides with EDF . Thirdly , that the line AC coincides with DF . And lastly , from these he shows that BC must coincide with EF . Hence the triangle ABC coincides with DEF . This is one of the most important results in Book ...
... angle BAC coincides with EDF . Thirdly , that the line AC coincides with DF . And lastly , from these he shows that BC must coincide with EF . Hence the triangle ABC coincides with DEF . This is one of the most important results in Book ...
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... angle BAC shall be equal to the angle EDF . B For if the triangle ABC be applied to the 2 , 3. triangle DEF , so that the point B may be on E , and the straight line BC on the straight line EF , the point C will also coincide with the ...
... angle BAC shall be equal to the angle EDF . B For if the triangle ABC be applied to the 2 , 3. triangle DEF , so that the point B may be on E , and the straight line BC on the straight line EF , the point C will also coincide with the ...
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... angle BAG = BGA because BA = BG , and the angle GAC = AGC because AC - GC . Therefore the whole anglo BAC - BGC , that is EDF . Q.E.D. Ex . 1. The diagonal of a rhombus bisects each of the angles through which it passes . Hence show ...
... angle BAG = BGA because BA = BG , and the angle GAC = AGC because AC - GC . Therefore the whole anglo BAC - BGC , that is EDF . Q.E.D. Ex . 1. The diagonal of a rhombus bisects each of the angles through which it passes . Hence show ...
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Euclides Charles MANSFORD. PROPOSITION 9. PROBLEM . To bisect a given rectilineal angle , that is to divide it into two equal angles . 1 . to bisect it . Let BAC be the given rectilineal angle . It is required A 2 . Take any point D in ...
Euclides Charles MANSFORD. PROPOSITION 9. PROBLEM . To bisect a given rectilineal angle , that is to divide it into two equal angles . 1 . to bisect it . Let BAC be the given rectilineal angle . It is required A 2 . Take any point D in ...
Otras ediciones - Ver todas
A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes ... Euclides Vista completa - 1874 |
A School Euclid, Being Books I. & II. of Euclid's Elements, with Notes by C ... Euclides Sin vista previa disponible - 2015 |
Términos y frases comunes
AC is equal adjacent angles alternate angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal angles are equal angles CBA axioms base BC BC is equal bisect centre circle coincide Const diagonals diameter double equal sides equal to BC equal to twice equilateral triangle Euclid exterior angle fore four right angles given point given rectilineal angle given straight line gnomon half a right hypotenuse interior and opposite isosceles triangle join Let ABC Let the straight obtuse opposite angle opposite sides parallel to CD parallelogram parallelogram ABCD perpendicular produced prop PROPOSITION quadrilateral rectangle AC rectangle contained remaining angle rhombus right angles right-angled triangle shew side BC sides equal square described square on AC THEOREM third angle triangle ABC triangle DEF truths twice the rectangle unequal