A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes, Exercises and Explanations ... By C. Mansford1874 |
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Página 22
... angle EDF , the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , B and the other angles shall be equal each to each , to which the equal sides are opposite , namely , the angle ABC to the angle DEF ...
... angle EDF , the base BC shall be equal to the base EF , and the triangle ABC to the triangle DEF , B and the other angles shall be equal each to each , to which the equal sides are opposite , namely , the angle ABC to the angle DEF ...
Página 23
... angle BAC coincides with EDF . Thirdly , that the line AC coincides with DF . And lastly , from these he shows that BC must coincide with EF . Hence the triangle ABC coincides with DEF . This is one of the most important results in Book ...
... angle BAC coincides with EDF . Thirdly , that the line AC coincides with DF . And lastly , from these he shows that BC must coincide with EF . Hence the triangle ABC coincides with DEF . This is one of the most important results in Book ...
Página 28
... angle BAC shall be equal to the angle EDF . B For if the triangle ABC be applied to the 2 , 3. triangle DEF , so that the point B may be on E , and the straight line BC on the straight line EF , the point C will also coincide with the ...
... angle BAC shall be equal to the angle EDF . B For if the triangle ABC be applied to the 2 , 3. triangle DEF , so that the point B may be on E , and the straight line BC on the straight line EF , the point C will also coincide with the ...
Página 29
... angle BAG = BGA because BA = BG , and the angle GAC = AGC because AC - GC . Therefore the whole anglo BAC - BGC , that is EDF . Q.E.D. Ex . 1. The diagonal of a rhombus bisects each of the angles through which it passes . Hence show ...
... angle BAG = BGA because BA = BG , and the angle GAC = AGC because AC - GC . Therefore the whole anglo BAC - BGC , that is EDF . Q.E.D. Ex . 1. The diagonal of a rhombus bisects each of the angles through which it passes . Hence show ...
Página 46
... angle BAC greater than the angle EDF ; the base BC shall be greater than the base EF . Of the two sides DE , DF , let DE be the side 2 . which is not greater than the other . At the point D in the straight line DE , make the angle EDG ...
... angle BAC greater than the angle EDF ; the base BC shall be greater than the base EF . Of the two sides DE , DF , let DE be the side 2 . which is not greater than the other . At the point D in the straight line DE , make the angle EDG ...
Otras ediciones - Ver todas
A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes ... Euclides Vista completa - 1874 |
A School Euclid, Being Books I. & II. of Euclid's Elements, with Notes by C ... Euclides Sin vista previa disponible - 2015 |
Términos y frases comunes
ABCD AC is equal alternate angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal apply axioms base BC bisect BOOK called centre circle coincide common Const construction definitions demonstration describe diagonals diameter difference divided double draw equal sides equilateral triangle Euclid exercise exterior angle fall figure fore geometry given point given rectilineal given straight line gnomon greater Hence isosceles triangle join length less Let ABC meet method namely opposite angle opposite sides parallel parallel to CD parallelogram perpendicular PROBLEM produced prop PROPOSITION proved quadrilateral reason rectangle contained rectilineal figure remainder result right angles side BC sides square on AC Take THEOREM things triangle ABC true truths twice the rectangle unequal units whole