A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes, Exercises and Explanations ... By C. Mansford |
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Página vi
If a leaf of paper be folded and divided into two equal parts by creasing it down the middle , the crease will represent a straight line . Now such a crease does not belong to either half of the paper , but simply divides one half from ...
If a leaf of paper be folded and divided into two equal parts by creasing it down the middle , the crease will represent a straight line . Now such a crease does not belong to either half of the paper , but simply divides one half from ...
Página x
Then follows the discussion , which may be divided into three parts to be thus distinguished . 1. The particular enunciation . 2. The construction . 3. The demonstration . The demonstration is effected by combining the elementary truths ...
Then follows the discussion , which may be divided into three parts to be thus distinguished . 1. The particular enunciation . 2. The construction . 3. The demonstration . The demonstration is effected by combining the elementary truths ...
Página 23
Prove by the method used in this proposition that the two triangles into which a square is divided by its diagonal are equal to one another . 2 . The diagonals of a square are equal to one another . PROPOSITION 5. THEOREM .
Prove by the method used in this proposition that the two triangles into which a square is divided by its diagonal are equal to one another . 2 . The diagonals of a square are equal to one another . PROPOSITION 5. THEOREM .
Página 31
Therefore the straight line AB is divided into two equal parts at the point D. Q.E.F. Ex . The straight line which bisects the vertical angle of an isosceles triangle also bisects the base at right angles . 3 PROPOSITION 11. PROBLEM .
Therefore the straight line AB is divided into two equal parts at the point D. Q.E.F. Ex . The straight line which bisects the vertical angle of an isosceles triangle also bisects the base at right angles . 3 PROPOSITION 11. PROBLEM .
Página 59
N.B. — In the case of a regular figure , as all its angles are equal , the value of an exterior angle will be found by dividing four right angles by the number of sides of the figure ; and if ...
N.B. — In the case of a regular figure , as all its angles are equal , the value of an exterior angle will be found by dividing four right angles by the number of sides of the figure ; and if ...
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A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes ... Euclides Vista completa - 1874 |
A School Euclid, Being Books I. & II. of Euclid's Elements, with Notes by C ... Euclides Sin vista previa disponible - 2015 |
Términos y frases comunes
ABCD AC is equal angle ABC angle ACB angle BAC angle BCD angle EDF angle equal apply axioms base BC bisect BOOK called centre circle coincide common Const construction definitions demonstration describe diagonals diameter difference divided double draw drawn equal sides equilateral triangle Euclid exercise exterior angle fall figure fore geometry given point given rectilineal given straight line gnomon greater half Hence isosceles triangle join length less Let ABC meet method namely opposite angle opposite sides parallel parallel to CD parallelogram perpendicular PROBLEM produced prop PROPOSITION proved quadrilateral reason rectangle contained rectilineal figure result right angles side BC sides square on AC Take THEOREM things triangle ABC true truths twice the rectangle unequal units whole
Información bibliográfica
| Título | A School Euclid. Being Books I.&II. of Euclid's Elements. With Notes, Exercises and Explanations ... By C. Mansford |
| Autor | Euclides |
| Editor | Charles MANSFORD |
| Publicado | 1874 |
| Procedencia del original | Biblioteca Británica |
| Digitalizado | 27 Nov. 2020 |
| Exportar cita | BiBTeX EndNote RefMan |