The synoptical Euclid; being the first four books of Euclid's Elements of geometry, with exercises, by S.A. Good1853 |
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Página 23
... reason , 2. The exterior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than CEB ; much more then 3. The angle BDC is greater than the angle BAC . Therefore , if from the ...
... reason , 2. The exterior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than CEB ; much more then 3. The angle BDC is greater than the angle BAC . Therefore , if from the ...
Página 35
... reason , EF is equal to BC ; wherefore ( Ax . 1. ) 1. AD is equal to EF ; The parallelograms ABCD , DBCF , are equal to one and DE is common ; therefore ( Ax . 2. or 3. ) 2. The whole , or the remainder , AE is equal to the whole , or ...
... reason , EF is equal to BC ; wherefore ( Ax . 1. ) 1. AD is equal to EF ; The parallelograms ABCD , DBCF , are equal to one and DE is common ; therefore ( Ax . 2. or 3. ) 2. The whole , or the remainder , AE is equal to the whole , or ...
Página 36
... reason 5. The parallelogram EFGH is equal to the same EBCH . Therefore also 6. The parallelogram ABCD is equal to EFGH . Wherefore , parallelograms , & c . Q.E.D. PROP . XXXVII . - THEOREM . Triangles upon the same base and between the ...
... reason 5. The parallelogram EFGH is equal to the same EBCH . Therefore also 6. The parallelogram ABCD is equal to EFGH . Wherefore , parallelograms , & c . Q.E.D. PROP . XXXVII . - THEOREM . Triangles upon the same base and between the ...
Página 40
... reason , E B H G 1 . Because ABCD is a parallelogram , and AC its diameter , ( I. 34. ) The triangle ABC is equal to the triangle ADC ; and because EKHA is a parallelogram , the diameter of which is AK , 2. The triangle AEK is equal to ...
... reason , E B H G 1 . Because ABCD is a parallelogram , and AC its diameter , ( I. 34. ) The triangle ABC is equal to the triangle ADC ; and because EKHA is a parallelogram , the diameter of which is AK , 2. The triangle AEK is equal to ...
Página 44
... reason B H D L E On BC describe ( I. 46. ) the square BDEC , and on BA , AC , the squares GB , HC ; through △ draw ( I. 31. ) AL parallel to BD , or CE , and join AD , FC . . K Then , because each of the angles BAC , BAG , is a right ...
... reason B H D L E On BC describe ( I. 46. ) the square BDEC , and on BA , AC , the squares GB , HC ; through △ draw ( I. 31. ) AL parallel to BD , or CE , and join AD , FC . . K Then , because each of the angles BAC , BAG , is a right ...
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Términos y frases comunes
ABCD AC is equal AF is equal angle ABC angle ACB angle BAC angle BCD angle equal base BC bisected centre circle ABC circumference coincide common demonstrated describe diameter distance divided double draw equal angles equal Constr exterior angle extremity fall figure four given circle given point given straight line given triangle greater impossible inscribed join less Let ABC likewise manner meet opposite angles parallel parallelogram pass pentagon perpendicular point F produced Q.E.D. PROP reason rectangle contained rectilineal figure remaining angle required to describe right angles segment semicircle shown side BC sides square of AC straight line AC touches the circle triangle ABC twice the rectangle wherefore whole
Pasajes populares
Página 26 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal...
Página 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Página 32 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 1 - A plane superficies is that in which any two points being taken, the straight line between them lies wholly in that superficies. vm. "A plane angle is the inclination of two lines to one another in a plane, which meet together, but are not in the same direction.
Página 97 - If from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Página 7 - AB; but things which are equal to the same are equal to one another...
Página 14 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Página 53 - IF a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part.
Página 41 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 52 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced...