 | Adrien Marie Legendre - 1822 - 394 páginas
...demonstration proves the angle BAD=DAC, and the angle BDA=ADC. Hence the two 172 last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to that base, and bisects the opposite angle. PROPOSITION XVI. THEOREM. In a spherical... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 294 páginas
...then cannot be supposed unequal to AC; therefore the sides AB, AC, opposite to the equal angles B, C, are equal. 484. Scholium. It is evident, from the...triangle to the middle of the base, is perpendicular to this base, and divides the angle opposite into two equal parts. I s~ THEOREM. I ' 485. In any spherical... | |
 | Adrien Marie Legendre - 1825 - 276 páginas
...then cannot be supposed unequal to AC; therefore the sides AB, AC, opposite to the equal angles B, C, are equal. 484. Scholium. It is evident, from the...from the vertex of an isosceles spherical triangle to ihe middle of the base, is perpendicular to this base, and divides the angle opposite into two equal... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 páginas
...cannot be supposed unequal to AC; therefore the sides AB, AC, opposite to the equal angles B, C, arc equal. 484. Scholium. It is evident, from the same...from the vertex of an isosceles spherical triangle to ihe middle of the base, is perpendicular to this base, and divides the angle opposite into two equal... | |
 | Dionysius Lardner - 1828 - 434 páginas
...sides, they will be symmetrically equal, and the proposition has been already proved. (152.) Cor. Hence the arc drawn from the vertex of an isosceles spherical triangle to the point of bisection of the base, bisects the vertical angle, and is perpendicular to the base. * In... | |
 | Adrien Marie Legendre - 1836 - 394 páginas
...demonstration proves the angle BAD = DAC, and the angle BDA— ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to that base, and bisects the vertical angle. PROPOSITION XIV. THEOREM. In any spherical... | |
 | Benjamin Peirce - 1837 - 216 páginas
...Corollary. Also the angle ADB = ADC, and, therefore, each is a right angle ; and also DAB = DAC, that . is> The arc, drawn from the vertex of an isosceles spherical...triangle to the middle of the base, is perpendicular to the base, and bisects the angle at the vertex. 454. Corollary. An equilateral spherical triangle... | |
 | Adrien Marie Legendre - 1841 - 288 páginas
...then cannot be supposed unequal to AC ; therefore the sides AB, AC, opposite to the equal angles B, C, are equal. 484. Scholium. It is evident, from the...triangle to the middle of the base, is perpendicular to this base, and divides the angle opposite into two equal parts. THEOREM. . 232. 485. In any spherical... | |
 | Nathan Scholfield - 1845 - 542 páginas
...demonstration proves the angle BAD =DAC, and the angle BDA— ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to the base, and bisects the vertical angle. PROPOSITION XVI. THEOREM. In any spherical... | |
 | Nathan Scholfield - 1845 - 244 páginas
...demonstration proves the angle BAD =DAC, and the angle BDA=ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to the base, and bisects the vertical angle. PROPOSITION XVI. THEOREM. In any spherical... | |
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In any spherical triangle, the greater side is opposite the greater angle ; and conversely, the greater angle is opposite the greater side. 
