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" Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer... "
Practical and Mental Arithmetic on a New Plan: In which Mental Arithmetic is ... - Página 187
por Roswell Chamberlain Smith - 1837 - 284 páginas
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The American Tutor's Guide: Being a Compendium of Arithmetic. In Six Parts ...

James Thompson - 1808 - 176 páginas
...second term. Then multiply the second and third terms together, and divide the product by the first. The quotient will be the fourth term or answer, in the same name or denomination as the second term was left in. Note — The first term is always known by the...
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The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1810 - 222 páginas
...requiring less. RULE. Multiply the second and third terms together, and divide the produit by the first ; the quotient will be the fourth term, or answer : in the same name with the second. PROOF. Invert the question, beginning with the answer ; and the result will be...
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The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 210 páginas
...lowest thereof: then multiply the second and third terms together, and divide the product by the first ; the' quotient will be the fourth term, or answer, in the same denomination as the second, or that to which the second is reduced. * The following rule for stating- and solving...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ...

Nathan Daboll - 1813 - 244 páginas
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term...
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Easy Introduction to Mathematics, Volumen1

Charles Butler - 1814 - 540 páginas
...mentioned 'in it. IV. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term, or answer, in the same denomination into which the second term was reduced. are the two means, and their product, viz. 4 X 3, equals the...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 páginas
...terms to the same denomination, aiid reduce the second term to the lowest name ir.antioned in it. 3. Multiply the second and third terms together, and...product by the first term ; the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1818 - 246 páginas
...terms to the same denomination, and reduce the second term to the lowest naiae mentioned in it. 3. Multiply the second and third terms together, and...product by the first term, the quotient will be the answer to the question, in fue same denomination you left the second term in, which may be brought...
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Arithmetic Modernised: Or, A Complete System of Arithmetic, Adapted to ...

John Davidson, Robert Scott (writing master) - 1818 - 190 páginas
...write the greater as thefirst, and the other as the second proportional. The numbers being thus stated, multiply the second and third terms together, and divide their product by thefirst, the quotient will be the answer, in ihe same name in which the third term is9 when you arc...
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A New and Concise System of Arithmetick: Containing Vulgar, Decimal, and ...

Beriah Stevens - 1822 - 436 páginas
...extreme is the divisor. 3. Place the divisor on the left hand, and the other extreme on the right ; then multiply the second and third terms together, and divide their product by the first, ami the quotient gives the answer ; which is always of the same name with the middle term. When the...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1824 - 264 páginas
...third terms to the same denomination, and reduce the second term to the lowest name mentioned in it. 3. Multiply the second and third terms together, and...their product by the first term ; the quotient will b« the answer to the question, in the same denomination you left the second term in, which may be...
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