Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J. Pryde. [With] Key1860 |
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... whole more complete , several important Corollaries have been added ; and , lastly , a number of instructive Exercises are annexed to each Book , to enable the Teacher to test the skill and inventive powers of the Pupil . Edinburgh ...
... whole more complete , several important Corollaries have been added ; and , lastly , a number of instructive Exercises are annexed to each Book , to enable the Teacher to test the skill and inventive powers of the Pupil . Edinburgh ...
Página 6
... whole is greater than its part . 10. All right angles are equal to one another . 10 11. Two straight lines cannot be drawn through the same point , parallel to the same straight line , without coinciding with one another . 12. It is ...
... whole is greater than its part . 10. All right angles are equal to one another . 10 11. Two straight lines cannot be drawn through the same point , parallel to the same straight line , without coinciding with one another . 12. It is ...
Página 9
... the point F , because AC is equal to DF : but the point B coincides with the point E ; wherefore the base BC shall coincide with the base EF ( Def . 3 ) , and shall be equal to it . Therefore , also , the whole FIRST BOOK . 9.
... the point F , because AC is equal to DF : but the point B coincides with the point E ; wherefore the base BC shall coincide with the base EF ( Def . 3 ) , and shall be equal to it . Therefore , also , the whole FIRST BOOK . 9.
Página 10
... whole AF is equal to the whole AG , and the part AB to the part AC , the remainder BF shall be equal ( Ax . 3 ) to the remainder CG ; and FC was proved to be equal to GB ; therefore the two sides BF and FC are equal to the two CG and GB ...
... whole AF is equal to the whole AG , and the part AB to the part AC , the remainder BF shall be equal ( Ax . 3 ) to the remainder CG ; and FC was proved to be equal to GB ; therefore the two sides BF and FC are equal to the two CG and GB ...
Página 27
... whole exterior angle ACD is equal to the two interior and opposite angles CAB and ABC . To each of these equals add the angle ACB , and the two angles ACD and ACB are equal to the three angles CBA , BAC , and ACB ; but the angles ACD ...
... whole exterior angle ACD is equal to the two interior and opposite angles CAB and ABC . To each of these equals add the angle ACB , and the two angles ACD and ACB are equal to the three angles CBA , BAC , and ACB ; but the angles ACD ...
Otras ediciones - Ver todas
Euclid's Elements of Plane Geometry [Book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde Sin vista previa disponible - 2023 |
Euclid's Elements of Plane Geometry [book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde Sin vista previa disponible - 2018 |
Términos y frases comunes
ABCD adjacent angles angle ABC angle ACB angle BAC apothem base BC BC is equal bisected centre Chambers's chord circle ABC circumference Const cosec cosine described diameter divided double draw equal angles equal to twice equiangular equilateral equilateral polygon equimultiples exterior angle fore given line given point given straight line gnomon greater hence hypotenuse inscribed isosceles triangle less line drawn multiple number of sides opposite angle parallel parallelogram perimeter perpendicular polygon produced proportional PROPOSITION prove radius ratio rectangle contained rectilineal figure regular polygon remaining angle right angles right-angled triangle segment semiperimeter shewn similar sine square on AC straight line AC tangent THEOREM third touches the circle triangle ABC triangle DEF twice the rectangle vertical angle wherefore
Pasajes populares
Página 23 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Página 52 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square of half the line bisected, is equal to the square of the straight line which is made up of the half and the part produced.
Página 51 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Página 53 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C ; the squares of AB, BC are equal to twice the rectangle AB, BC...
Página 3 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Página 29 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 117 - And the same thing is to be understood when it is more briefly expressed by saying, a has to d the ratio compounded of the ratios of e to f, g to h, and k to l. In like manner, the same things being supposed, if m has to n the same ratio which a has to d ', then, for shortness...
Página 13 - Upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity.
Página 159 - From the point A draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so is (2.
Página 60 - CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i.