 | Adrien Marie Legendre - 1819 - 574 páginas
...on equal spheres, are equal in all their parts, when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. . 230. Demonstration. Let the side AB = EF (Jig. 23O), the side AC = EG, and the angle BAC = FEG, the... | |
 | Adrien Marie Legendre - 1825 - 276 páginas
...-vertical angles. 36. Two triangles arc. equal, -when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. Demonstration. In the two triangles ABC, DEF (fig. 23), let Fig. 23. the angle A be equal to the angle... | |
 | Adrien Marie Legendre, John Farrar - 1825 - 280 páginas
...on equal spheres, are equal in all their parts, when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. Fig. 230. Demonstration. Let the side AB = EF (fig. 230), the side AC = EG, and the angle BAC = PEG,... | |
 | Adrien Marie Legendre - 1841 - 288 páginas
...angles. THEOREM. 36. Two triangles are equal, when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. Demonstration. In the two triangles ABC, DEF (fig. 23), Fig. 23 let the angle A be equal to the angle... | |
 | Charles Waterhouse - 1842 - 178 páginas
...Demonstrably true: — 1. Two triangles are equal when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. 2. In an isosceles triangle, the angles opposite to the equal sides are equal. 3. Of the two sides... | |
 | Charles WATERHOUSE - 1844 - 228 páginas
...opposite the longer aids. 6. Two triangles ore equal when two sides and the included angle of the one are equal to two sides and the included angle of the other, each to each. 7. Every triangle is half of a parallelogram of the same base and altitude. 8. In a right-angled triangle,... | |
 | Charles Davies - 1849 - 372 páginas
...on equal spheres, are equal in all their parts, when two sides and the included angle of the one are equal to two sides and the included angle of the other each to each. For, the triangle EFG may be placed on the triangle ABCi or on ABD symmetrical with ABC, just as two... | |
 | Charles Davies - 1850 - 218 páginas
...AD—BC, by hypothesis, the side AB common, and the angle A equal to the angle B : hence the two triangles have two sides and the included angle of the one equal...included angle of the other, each to each : hence, the two triangles are equal (Th. iv), that is, a part ADB is equal to the whole ABC, which is impossible... | |
 | Charles Davies - 1850 - 238 páginas
...AD=BC, by hypothesis, the side AB common, and tho angle A equal to the angle B : hence the two triangles have two sides and the included angle of the one equal...included angle of the other, each to each : hence, the two triangles are equal (Th. iv), that is, a part ADB is equal to the whole ABC, which is impossible... | |
 | Charles Davies - 1886 - 340 páginas
...by hypothesis; the s1de AB common, and the angle A equal to the angle B : hence, the two triangles have two sides and the included angle of the one equal...included angle of the other, each to each : hence, the two trIangles are equal (Th- iv), that is, a part ADB is equal to the whole ABC, which is impossible... | |
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B : hence the two triangles have two sides and the included angle of the one equal to two sides and the included angle of the other, each to each : hence, the two triangles are equal (Th. 
