PAPER I. (Second Mate as far as Longitude by Chronometer.) Multiply 1957 by 600 by common logarithms. Divide 27850 by .2785 by common logarithms. 1885. April 16th, in long. 14° 20′ W.; the observed meridian altitude of the sun's lower limb was 45° 3′ 15′′ bearing S., index error 2' 10" to add; height of eye 21 feet. Required the Latitude. In lat. 44° 16' N., the departure made good was 183 miles. Required the Difference of Longitude by Parallel Sailing. Required the Course and Distance from A to B on Mercator's principle. Lat. of A 52° 10' N. Long. of A 16° 13′ W. Lat. of B 41 59 S. Long. of B 21 12 W. PAPER I.-Continued. 1884. March 1st. Find the time of High Water at Ballycastle Bay, A.M. and P.M. 1885. March 19th, at 6h om P.M., apparent time at ship in lat. 24° 5' N.; long. 27° 30′ W.; the sun's observed altitude was W.N.W. Required the True Amplitude and Error of the Compass; and supposing the variation to be 27° 17′ W., required the Deviation of the Compass for the position of ship's head at the time of observation. 1885. July 1st, A.M., at ship in lat. 30° 20' N.; the observed altitude of the sun's lower limb was 50° 18' o"; height of eye 14 feet. Time by a chronometer July Id 2h 16m 30s; which was 17 20° fast for mean noon at Greenwich on January 13th, and gaining 3% daily. Required the Longitude. ADDITIONAL FOR ONLY AND FIRST MATES. 1885. September 23rd, P.M., Mean Time at Greenwich 22d 16h 6m 203 in lat. 40° N.; long. 162° 10′ E.; the sun's bearing by compass W. S.; observed altitude of the sun's lower limb 32° 8′ 20′′; height of eye 20 feet. Required the true Azimuth and Error of the Compass; and supposing the variation to be 20° o' W., required the Deviation of the Compass for the position of the ship's head at the time of the observation. 1885. July 1st, A.M. at ship, lat. by account 50° 13' N.; long. 35° W.; the observed altitude of the sun's lower limb 62° 20' 30" South of the observer; height of eye 15 feet. Time by Chronometer 1d 2 2 52, which was I 26s fast on Mean Time at Greenwich. Required the Latitude by the Reduction to the Meridian. h ADDITIONAL FOR Master. 1885. February 15th. The observed meridian altitude of the star "Aldebaran" bearing South, was 50° 20′ 30′′; height of the eye 20 feet. Required the Latitude. PAPER I. Continued. Find the Index Error and Sun's Semidiameter from the following readings of the Sextant: 31′ 20′′ on and 32' 10" off. NAPIER'S DIAGRAM. ADDITIONAL FOR MASTER. In the following Table give the correct magnetic bearing of the distant object, and thence the deviation. CORRECT MAGNETIC BEARING: With the deviation as above, give the courses you would steer by the standard compass to make the following courses, correct magnetic. Correct magnetic courses, N N E., South, EN. Suppose you have steered the following courses by the standard compass, find the correct magnetic courses made from the above deviation table. Compass courses S W W., W N W., North. יד You have taken the following bearings of two distant obejcts by your standard compass as above; with the ship's head at N.E., find the bearings, correct magnetic. Compass bearings N E., West. Bearings, magnetic SUMNER'S METHOD.-PAPER I.-Continued. FOR MASTER, FIRST MATE AND ONLY MATE. If at sea on March 4th, 1885, A.M., and uncertain of my position when the Chronometer shewed 3d 21h 0m 59s G.M.T., the observed Altitude of the Sun's L.L. was 17° 0' 44", and again P.M., the same day, when the Chronometer shewed 4d2h 29m os G.M.T, the observed Altitude of the Sun's L.L. 31° 17′ 47′′, the ship having made 17 miles on a true N. E. course in the interval, height of eye 20 feet. Required the line of position when the first Altitude was taken, also the bearing of the Sun by projection, and the Latitude and Longitude of the ship when the second Altitude was observed. The ship being supposed to be between the parallels of 47° 20′ N. and 47° 50' N. True Chart. 1. Using deviation card No. find the course to steer by Compass from G to S, also the distance. 2. With the ship's head on the above-named compass course, a [point] [lighthouse] B bore by compass N 63° 45′ E. and C bore S 26° 15′ E. by the same compass. Find the ship's position. 3. With the ship's head as above, a [point] [lighthouse] H bore by compass S 75° W., and after continuing on the same course 15 miles, it bore N 71° W. Find the Ship's position, and her distance from H, at the time of taking the second bearing. ADDITIONAL FOR MASTERS. 4. Find the course to steer by compass from G to S (See Question 1.) to counteract the effect of a current, which set S.W. (true) at the rate of 23 miles per hour, the ship making by log 8 miles per hour; also the distance the ship will then make good in 4 hours towards S. 5.-On August 25th, 1884, at 9" A.M., being off Christchurch, by reckoning took a cast of the lead. Required the correction to be applied to the depth obtained by the lead line before comparing it with the depth marked on the chart. PAPER II. (Second Mate as far as Longitude by Chronometer.) Multiply 20006 by 55 by common logarithms. Divide 1986048 by 72 by common logarithms. 1885. March 20th, in long. 16° 40' E.; the observed meridian altitude of the sun's lower limb was 36° 20' 0", bearing South, index error-1′ 20′′; height of eye 16 feet. Required the latitude. In lat. 45° 17' S. the departure made good was 38.7 miles. Required the difference of Longitude by Parallel Sailing. Required the Course and Distance from A to B on Mercator's principle. Lat. of A 11° 30′ N. Lat. of B 5 30 N. Long. of A 73° 20' E. |
