A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Página 98
... ABCD 204.326 ABCD 102.163 Ch . 10A . OR . 34.6P . 2. In a trapezium ABCD , the angles are , A = 65o , B = 81o , C = 120 ° , and consequently D = 94 ° ; also the side AB = 20 Ch . and CD = 11 Ch .: required the area . Ans . 22A . 2R ...
... ABCD 204.326 ABCD 102.163 Ch . 10A . OR . 34.6P . 2. In a trapezium ABCD , the angles are , A = 65o , B = 81o , C = 120 ° , and consequently D = 94 ° ; also the side AB = 20 Ch . and CD = 11 Ch .: required the area . Ans . 22A . 2R ...
Página 100
... ABCD , there are given AD = 23.32 Ch . , AB = 25.70 Ch . , and BC 15.84 Ch . , the angle DAB = 64 ° and ABC = 82 ... ABCD + 2 EAD ; therefore in this case ABFD + ABCE 2 ABCD + 2 EAD ; or ABFD + ABCE - 2 EAD 2 ABCD . - And , Fig . 73 ...
... ABCD , there are given AD = 23.32 Ch . , AB = 25.70 Ch . , and BC 15.84 Ch . , the angle DAB = 64 ° and ABC = 82 ... ABCD + 2 EAD ; therefore in this case ABFD + ABCE 2 ABCD + 2 EAD ; or ABFD + ABCE - 2 EAD 2 ABCD . - And , Fig . 73 ...
Página 102
... ABCD , of which the parallel sides AD , BC measure 6.14 and 9.48 chains respectively , and their perpendicular distance BF or DE , 7.80 chains . Ch . 6.14 9.48 15.62 7.80 124960 10934 2 ) 121.8-60 60.9180 Ch . 6A . OR . 15P ...
... ABCD , of which the parallel sides AD , BC measure 6.14 and 9.48 chains respectively , and their perpendicular distance BF or DE , 7.80 chains . Ch . 6.14 9.48 15.62 7.80 124960 10934 2 ) 121.8-60 60.9180 Ch . 6A . OR . 15P ...
Página 140
... ABCD within the stationary lines will be found , by either of the rules in the preceding sec- tion , to be 18 A. 1 R. 11 P. * DEMONSTRATION . Considering the boundary as straight between the ends of each two adjacent off - sets , it is ...
... ABCD within the stationary lines will be found , by either of the rules in the preceding sec- tion , to be 18 A. 1 R. 11 P. * DEMONSTRATION . Considering the boundary as straight between the ends of each two adjacent off - sets , it is ...
Página 141
... 1.25 2.93 3.6625 10 14.45 0.35 2.74 2.20 6.0280 2 ) 37.6144 18.8072 Ch . = 1A . 3 R. 21 P. A. P. R. Area of ABCD · 13 1 11 Do. of off - sets · 1 3 21 Whole area : 15 0 32 EXAMPLE 2. Fig . 83 . Required the area of די MEASURING LAND . 141.
... 1.25 2.93 3.6625 10 14.45 0.35 2.74 2.20 6.0280 2 ) 37.6144 18.8072 Ch . = 1A . 3 R. 21 P. A. P. R. Area of ABCD · 13 1 11 Do. of off - sets · 1 3 21 Whole area : 15 0 32 EXAMPLE 2. Fig . 83 . Required the area of די MEASURING LAND . 141.
Términos y frases comunes
ABCD ABFD acres adjacent adjacent angles angle ABC angle opposite angled triangle base bearing and distance breadth Calculation centre Co-secant Secant Co-sine Co-tang column cube root decimal DEMONSTRATION departure corresponding diff difference of latitude Dist divide division line draw equal EXAMPLES feet figures find the angle find the area four-pole chains fourth term given angle given area given bearing given number given ratio given side John Gummere Lat Dep latitude and departure length logarithm M.
M. Sine measured meridian distance natural number off-sets parallel parallelogram perches perpendicular quired quotient radius rectangle remainder Required the area right angle right line right-angled triangle RULE semiperimeter side AB side AC square root station stationary line subtract survey tance Tang tangent tract of land trapezium trapezoid triangle ABC trigonometry