A System of Geometry and Trigonometry: Together with a Treatise on Surveying : Teaching Various Ways of Taking the Survey of a Field : Also to Protract the Same and Find the Area : Likewise, Rectangular Surveying, Or, an Accurate Method of Calculating the Area of Any Field Arithmetically, Without the Necessity of Plotting it : to the Whole are Added Several Mathematical Tables, with a Particular Explanation and the Manner of Using Them : Compiled from Various AuthorsOliver D. Cooke, 1804 - 168 páginas |
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Página 8
... Problems and Rules for dividing Land and determining the true Course and Distance of dividing Lines , or from one part of a Field to another . To this are added some observations res-- pecting the Variation of the Compass and the Attrac ...
... Problems and Rules for dividing Land and determining the true Course and Distance of dividing Lines , or from one part of a Field to another . To this are added some observations res-- pecting the Variation of the Compass and the Attrac ...
Página 14
... Problems . PROBLEM I. To draw a Line parallel to another Line , at any given distance ; as at the Point D , to make a Line parallel to the Line AB . PLATE 1. Fig . 22 . With the Dividers take the nearest distance between the Point D and ...
... Problems . PROBLEM I. To draw a Line parallel to another Line , at any given distance ; as at the Point D , to make a Line parallel to the Line AB . PLATE 1. Fig . 22 . With the Dividers take the nearest distance between the Point D and ...
Página 15
... PROBLEM III . To erect a Perpendicular from the end , or any part of a given Line . Fig . 24 . Open the Dividers to any convenient distance , as from D to A , and with one foot on the Point D , from which the Perpendicular is to be ...
... PROBLEM III . To erect a Perpendicular from the end , or any part of a given Line . Fig . 24 . Open the Dividers to any convenient distance , as from D to A , and with one foot on the Point D , from which the Perpendicular is to be ...
Página 16
... PROBLEM VII . To make an Obtuse Angle , sup- pose of 110 Degrees . Fig . 28 . Take a Chord of 60 Degrees as before , and describe an Arch greater than a Quadrant ; set off 90 Degrees from B to C , and from C to E set off the excess ...
... PROBLEM VII . To make an Obtuse Angle , sup- pose of 110 Degrees . Fig . 28 . Take a Chord of 60 Degrees as before , and describe an Arch greater than a Quadrant ; set off 90 Degrees from B to C , and from C to E set off the excess ...
Página 17
... PROBLEM X. To make a Right Angled Triangle , the Angles and one Leg being given . Fig . 31 . Suppose the Angle at C 33 ° 15 ' , and the Leg AC 285 . Draw the Leg AC making it in length 285 ; at A erect a Perpendicular an indefinite ...
... PROBLEM X. To make a Right Angled Triangle , the Angles and one Leg being given . Fig . 31 . Suppose the Angle at C 33 ° 15 ' , and the Leg AC 285 . Draw the Leg AC making it in length 285 ; at A erect a Perpendicular an indefinite ...
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System of Geometry and Trigonometry: Together with a Treatise on Surveying ... Abel Flint Sin vista previa disponible - 2017 |
System of Geometry and Trigonometry: Together With a Treatise on Surveying ... Abel Flint Sin vista previa disponible - 2017 |
Pasajes populares
Página 28 - As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base.
Página 27 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Página 6 - The Circumference of every circle is supposed to be divided into 360 equal parts, called Degrees ; and each degree into 60 Minutes, each minute into 60 Seconds, and so on.
Página 24 - In this case the" hypothenuse may be found by the square root without finding the angles ; according to the following PROPOSITION. IN EVERY RIGHT ANGLED TRIANGLE, THE SUM OF THE SQUARES OF THE TWO LEGS IS EQUAL TO THE SQUARE OF THE HYPOTHENUSE. In the above EXAMPLE, the square of AB 78.7 is 6193.69, the square of BC 89 is 7921 ; these added make 14114,69 the square root of which is nearest 119.
Página 40 - Field work and protraction are truly taken and performed ; if not, an error must have been committed in one of them : In such cases make a second protraction ; if this agrees with the former, it is to be presumed the fault is in the Field work ; a re-survey must then be taken.
Página 33 - To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
Página 6 - Therefore all radii of the same circle are equal. 13. The diameter of a circle is a right line drawn from one side of the circumference to the other, passing through the centre ; and it divides the circle into two equal parts, called semicircles ; as AB or DE.
Página 40 - Let his attention first be directed to the map, and inform him that the top is north, the bottom south, the right hand east, and the left hand west.
Página 23 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.