## Elements of Geometry;: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids; to which are Added, Elements of Plane and Spherical TrigonometryBell & Bradfute, 1804 - 440 páginas |

### Dentro del libro

Resultados 6-10 de 73

Página 96

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**arches**, when they are at the centres ; therefore the**arch**BGC is equal to the**arch**EHF . But the whole circle ABC is equal to the whole EDF ; the remaining part , therefore , of the circumference , viz . BAC , is equal to the remaining ... Página 97

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**arch**, that is , to divide it into two equal parts . T it . Let ADB be the given**arch**; it is required to bisect Join AB , and bisecta it in C ; from the point C draw CD a 10. 1 . at right angles to AB , and join AD , DB : the**arch**... Página 98

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**arch**DB : and therefore the given**arch**ADB is bisected in D. Which was to be done . PROP . XXXI . THEOR . Igles Na circle , the angle in a semicircle is a right an- but the angle in a segment greater than a fe- micircle is less than ... Página 99

... take any point Cin the

... take any point Cin the

**arch**BD , and join AD , DC , CB ; and because the straight line EF touches the circle ABCD in the point B , and BA is drawn at right angles to the touching H2 E B D C F Book III . touching line OF GEOMETRY . 99. Página 119

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**arches**, therefore the**arch**BD is one tenth of the circumfe- rence ; and the straight line BD , that is AC , is therefore equal to the fide of an equilateral decagon inscribed in the circle BDE . " 40 I4 PROP . Book IV . PROP . ΧΙ ...### Otras ediciones - Ver todas

Elements of Geometry: Containing the First Six Books of Euclid, with a ... Formerly Chairman Department of Immunology John Playfair Sin vista previa disponible - 2015 |

### Términos y frases comunes

ABC is equal ABCD alfo alſo altitude angle ABC angle ACB angle BAC arch bafe baſe baſe BC becauſe becauſe the angle biſected Book cafe cauſe centre circle ABC circumference co-fine cof BC cylinder demonſtrated deſcribed diameter draw drawn equal angles equiangular equilateral polygon equimultiples Euclid exterior angle fame ratio fame reaſon fides fince firſt folid fore given ſtraight line greater inſcribed interfect join leſs Let ABC line BC magnitudes oppoſite parallel parallelepipeds parallelogram paſs paſſes perpendicular polygon priſm proportionals propoſition Q. E. D. PROP radius rectangle contained rectilineal figure remaining angle ſame ſame manner ſame plane ſecond ſegment ſemicircle ſhall ſhewn ſide ſolid ſpace ſphere ſpherical triangle ſquare ſtand ſuch ſum ſuppoſed tangent THEOR theſe thoſe touches the circle triangle ABC uſe wherefore

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