The Synoptical Euclid; Being the First Four Books of Euclid's Elements of Geometry, from the Edition of Dr. Robert Simson ... With ExercisesCharles Henry Law, 1854 - 120 páginas |
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Página 16
... describe ( Post . 3. ) the circle EGF meeting AB in F , G ; and bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . C E II G B D Join CF , CG ...
... describe ( Post . 3. ) the circle EGF meeting AB in F , G ; and bisect ( I. 10. ) FG in H , and join CH ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . C E II G B D Join CF , CG ...
Página 23
... describe ( Post . 3. ) the circle DKL ; and from the centre G , at the distance GH , describe another circle HLK ; and join KF , KG ; the triangle KFG has its sides equal to the three straight lines A , B , C. K D G H LA B C Because the ...
... describe ( Post . 3. ) the circle DKL ; and from the centre G , at the distance GH , describe another circle HLK ; and join KF , KG ; the triangle KFG has its sides equal to the three straight lines A , B , C. K D G H LA B C Because the ...
Página 39
... describe a parallelogram that shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle . Let ABC be the given triangle , and D the given rectilineal angle . It is required to describe a ...
... describe a parallelogram that shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle . Let ABC be the given triangle , and D the given rectilineal angle . It is required to describe a ...
Página 41
... Therefore the parallelogram LB is applied to the straight line AB , is equal to the triangle C , and has the angle ABM equal to the angle D. Which was to be done . PROP . XLV . - PROBLEM . To describe a BOOK I. PROP . XLIV . 41.
... Therefore the parallelogram LB is applied to the straight line AB , is equal to the triangle C , and has the angle ABM equal to the angle D. Which was to be done . PROP . XLV . - PROBLEM . To describe a BOOK I. PROP . XLIV . 41.
Página 42
... describe a parallelogram equal to ABCD , and having an angle equal to E. Join DB ; and describe ( I. 42. ) the parallelogram FH equal to the triangle ADB , and having the angle HKF equal to the angle E ; and to the straight line GH ...
... describe a parallelogram equal to ABCD , and having an angle equal to E. Join DB ; and describe ( I. 42. ) the parallelogram FH equal to the triangle ADB , and having the angle HKF equal to the angle E ; and to the straight line GH ...
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Términos y frases comunes
AB is equal AC is equal adjacent angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angle equal base BC bisected circle ABC circumference diameter double draw equal angles equal Constr equal Hyp equal straight lines equal to BC equilateral and equiangular EUCLID'S ELEMENTS exterior angle given circle given point given rectilineal angle given straight line given triangle gnomon greater inscribed interior and opposite less Let ABC Let the straight likewise opposite angles parallel to CD parallelogram pentagon perpendicular point F produced Q.E.D. PROP rectangle AE rectangle contained remaining angle required to describe right angles semicircle side BC square of AC straight line AB straight line AC straight line drawn touches the circle triangle ABC twice the rectangle