A graduated course of problems in practical plane and solid geometry |
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Página 11
... describe an arc cutting AB in C. 2. From centre C , with the same radius , cut the arc in D. 3. Draw the line DB . Then DBA is the required angle of 60 . 4. Bisect the angle DBA by the line EB ( PRACTICAL GEOMETRY . 11.
... describe an arc cutting AB in C. 2. From centre C , with the same radius , cut the arc in D. 3. Draw the line DB . Then DBA is the required angle of 60 . 4. Bisect the angle DBA by the line EB ( PRACTICAL GEOMETRY . 11.
Página 13
... describe an arc cutting AB in E. 2. From C as centre , with the same radius , describe an arc DF , and make arc DF equal to arc CE . 3. Draw the line FC , and it will be parallel to the given line AB . Problem 10 . From a given point D ...
... describe an arc cutting AB in E. 2. From C as centre , with the same radius , describe an arc DF , and make arc DF equal to arc CE . 3. Draw the line FC , and it will be parallel to the given line AB . Problem 10 . From a given point D ...
Página 23
... describe an arc BD . 2. From centre B , with the same radius , PRACTICAL GEOMETRY . 23.
... describe an arc BD . 2. From centre B , with the same radius , PRACTICAL GEOMETRY . 23.
Página 24
... arc in C. 3. Join AC and BC . Then ABC is the required equilateral triangle ... describe a semicircle cutting CAD in C and D. 3. From C and D with the same ... arc HG is 60 ° . Moreover , the three angles of a triangle , added together ...
... arc in C. 3. Join AC and BC . Then ABC is the required equilateral triangle ... describe a semicircle cutting CAD in C and D. 3. From C and D with the same ... arc HG is 60 ° . Moreover , the three angles of a triangle , added together ...
Página 29
... describe an arc meeting AC in F. 3. From F , draw a line FG parallel to AB ( Pr . 9 ) , and meeting BC in G. Then the given triangle ABC will be bisected by the line FG . Problem 28 . To construct an isosceles triangle on a given base ...
... describe an arc meeting AC in F. 3. From F , draw a line FG parallel to AB ( Pr . 9 ) , and meeting BC in G. Then the given triangle ABC will be bisected by the line FG . Problem 28 . To construct an isosceles triangle on a given base ...
Términos y frases comunes
altitude angles to xy Atlas axis base BC Pr Bisect the angle bound in cloth circumference cone construct a triangle cube curve cylinder decagon describe a circle describe an arc describe the arc diameter BC distance divide draw a line draw a tangent draw lines edge ellipse equal circles equal in area equilateral triangle given circle given line given point given square ABCD given straight line given triangle ABC heptagon horizontal plane hyperbola inclined inscribe intersection isosceles triangle Join line BC line CD line of bisection lines parallel Maps mean proportional meeting number of equal octahedron parallel to xy parallelogram pentagon perpendicular to xy Philips plan and elevation PLANE GEOMETRY plane of projection point F points of division prism Problem projectors pyramid radii radius rectangle rectilineal figure regular polygon represent required circle rhombus right angles semicircle SOLID GEOMETRY square pyramid trapezium vertical plane
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Página 193 - A cone is a solid figure described by the revolution of a right-angled triangle about one of the sides containing the right angle, which side remains fixed. If the fixed side be equal to the other side containing the right angle, the cone is called a right-angled cone ; if it be less than the other side, an obtuse-angled ; and if greater, an acute-angled cone. XIX. The axis of a cone is the fixed straight line about which the triangle revolves.
Página 123 - A straight line is said to be cut in extreme and mean ratio, when the whole is to the greater segment as the greater segment is to the less.