The Elements of Euclid, the parts read in the University of Cambridge [book 1-6 and parts of book 11,12] with geometrical problems, by J.W. Colenso1846 |
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Página 19
... join BE and produce it to F , making EF equal to BE ( 1. 3 ) ; and join FC . M B E с D Then , because AE is equal to EC , and BE to EF , the two sides , AE , EB , are equal to the two , CE , EF , each to each , and the angle AEB is ...
... join BE and produce it to F , making EF equal to BE ( 1. 3 ) ; and join FC . M B E с D Then , because AE is equal to EC , and BE to EF , the two sides , AE , EB , are equal to the two , CE , EF , each to each , and the angle AEB is ...
Página 20
... join BD : Then , because ADB is the exterior angle of the triangle BDC , it is greater than the interior and opposite angle DCB ( 1. 16 ) : But the angle ADB B A is equal to the angle ABD , because the side AD is equal to the side AB ...
... join BD : Then , because ADB is the exterior angle of the triangle BDC , it is greater than the interior and opposite angle DCB ( 1. 16 ) : But the angle ADB B A is equal to the angle ABD , because the side AD is equal to the side AB ...
Página 21
... CB , greater than AB . Produce BA to the point D , making AD equal to AC ( 1. 3 ) , and join DC . Then because AD is equal to AC , the angle ADC is equal to the angle ACD : B D But the angle BCD is greater than the angle ACD BOOK I. 21.
... CB , greater than AB . Produce BA to the point D , making AD equal to AC ( 1. 3 ) , and join DC . Then because AD is equal to AC , the angle ADC is equal to the angle ACD : B D But the angle BCD is greater than the angle ACD BOOK I. 21.
Página 23
... join KF , KG : the triangle KFG has its sides equal to the three straight lines A , B , C. Because the point F is the centre of the circle DKL , FD is equal to FK : but FD was made equal to A ; therefore also FK is equal to A : Again ...
... join KF , KG : the triangle KFG has its sides equal to the three straight lines A , B , C. Because the point F is the centre of the circle DKL , FD is equal to FK : but FD was made equal to A ; therefore also FK is equal to A : Again ...
Página 24
... join DE ; and make the triangle AFG , the sides of which shall be equal to the three straight lines CD , DE , EC ( 1. 22 ) , so that AF shall be equal to CD , AG to CE , and FG to DE : the angle FAG shall be equal to the angle DCE . E F ...
... join DE ; and make the triangle AFG , the sides of which shall be equal to the three straight lines CD , DE , EC ( 1. 22 ) , so that AF shall be equal to CD , AG to CE , and FG to DE : the angle FAG shall be equal to the angle DCE . E F ...
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The Elements of Euclid, the Parts Read in the University of Cambridge [Book ... Euclides Sin vista previa disponible - 2016 |
Términos y frases comunes
ABCD adjacent angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal base BC BC is equal centre chord circle ABC circumference cuts the circle diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given straight line gnomon greater ratio inscribed intersection isosceles triangle less Let ABC Let the straight lines be drawn lines drawn meet multiple opposite angles opposite sides parallel to BC parallelogram pentagon perpendicular plane polygon PROB produced proportionals Q.E.D. PROP rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn square of AC straight line &c straight line AB THEOR touches the circle triangle ABC twice the rectangle Wherefore
Pasajes populares
Página 42 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 4 - Let it be granted that a straight line may be drawn from any one point to any other point.
Página 33 - F, which is the common vertex of the triangles: that is », together with four right angles. Therefore all the angles of the figure, together with four right angles are equal to twice as many right angles as the figure has sides.
Página 62 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Página 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Página 58 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Página 146 - ... may be demonstrated from what has been said of the pentagon : and likewise a circle may be inscribed in a given equilateral and equiangular hexagon, and circumscribed about it, by a method like to that used for the pentagon.
Página 194 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Página 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Página 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.