A System of Geometry and Trigonometry: Together with a Treatise on Surveying : Teaching Various Ways of Taking the Survey of a Field : Also to Protract the Same and Find the Area : Likewise, Rectangular Surveying, Or, an Accurate Method of Calculating the Area of Any Field Arithmetically, Without the Necessity of Plotting it : to the Whole are Added Several Mathematical Tables, with a Particular Explanation and the Manner of Using Them : Compiled from Various AuthorsOliver D. Cooke, 1804 - 168 páginas |
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Página 15
... length ; from 2 Scale of Chords take 60 Degrees with the Dividers , and with one foot in B describe an Arch from the Line AB ; from the same Scale take the given number of Degrees , 36 , and lay it on the Arch from C to D ; draw a Line ...
... length ; from 2 Scale of Chords take 60 Degrees with the Dividers , and with one foot in B describe an Arch from the Line AB ; from the same Scale take the given number of Degrees , 36 , and lay it on the Arch from C to D ; draw a Line ...
Página 16
... length of the Line BO , describe an Arch as at O ; from L , with the length of the Line LO , describe another Arch to intercept the former ; from O draw the Lines OB and OL , and BOL will be the Triangle required . PROBLEM IX . To make ...
... length of the Line BO , describe an Arch as at O ; from L , with the length of the Line LO , describe another Arch to intercept the former ; from O draw the Lines OB and OL , and BOL will be the Triangle required . PROBLEM IX . To make ...
Página 17
... length 285 ; at A erect a Perpendicular an indefinite length ; at C make an Angle of 33 ° 15 ' ; through where that number of Degrees cuts the Arch draw a Line till it meets the Per- pendicular at B. Note . If the given Line CA should ...
... length 285 ; at A erect a Perpendicular an indefinite length ; at C make an Angle of 33 ° 15 ' ; through where that number of Degrees cuts the Arch draw a Line till it meets the Per- pendicular at B. Note . If the given Line CA should ...
Página 18
... length 98 ; on the Point B make an Angle of 45 ° 15 ′ ; on the point C make an Angle of 26 ° 15 ' , and draw the Lines BD and CD . PROBLEM XIV . To make an Oblique Angled Triangle , two sides and an Angle opposite to one of them being ...
... length 98 ; on the Point B make an Angle of 45 ° 15 ′ ; on the point C make an Angle of 26 ° 15 ' , and draw the Lines BD and CD . PROBLEM XIV . To make an Oblique Angled Triangle , two sides and an Angle opposite to one of them being ...
Página 21
... length of the Side given ; So is the name of the Side required , which also will be either Radius , Sine , Tangent or Secant ; To the length of the Side required . RULE II . To find an Angle one of the given Sides must be made Radius ...
... length of the Side given ; So is the name of the Side required , which also will be either Radius , Sine , Tangent or Secant ; To the length of the Side required . RULE II . To find an Angle one of the given Sides must be made Radius ...
Otras ediciones - Ver todas
System of Geometry and Trigonometry: Together with a Treatise on Surveying ... Abel Flint Sin vista previa disponible - 2017 |
System of Geometry and Trigonometry: Together With a Treatise on Surveying ... Abel Flint Sin vista previa disponible - 2017 |
Pasajes populares
Página 28 - As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base.
Página 27 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Página 6 - The Circumference of every circle is supposed to be divided into 360 equal parts, called Degrees ; and each degree into 60 Minutes, each minute into 60 Seconds, and so on.
Página 24 - In this case the" hypothenuse may be found by the square root without finding the angles ; according to the following PROPOSITION. IN EVERY RIGHT ANGLED TRIANGLE, THE SUM OF THE SQUARES OF THE TWO LEGS IS EQUAL TO THE SQUARE OF THE HYPOTHENUSE. In the above EXAMPLE, the square of AB 78.7 is 6193.69, the square of BC 89 is 7921 ; these added make 14114,69 the square root of which is nearest 119.
Página 40 - Field work and protraction are truly taken and performed ; if not, an error must have been committed in one of them : In such cases make a second protraction ; if this agrees with the former, it is to be presumed the fault is in the Field work ; a re-survey must then be taken.
Página 33 - To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area.
Página 6 - Therefore all radii of the same circle are equal. 13. The diameter of a circle is a right line drawn from one side of the circumference to the other, passing through the centre ; and it divides the circle into two equal parts, called semicircles ; as AB or DE.
Página 40 - Let his attention first be directed to the map, and inform him that the top is north, the bottom south, the right hand east, and the left hand west.
Página 23 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.