A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Página 37
... perpendicular to AB and produce it to F ; draw BE parallel to CF and join AD . Divide the arc AD into nine equal parts as A , 10 ; 10 , 20 ; & c . and with one foot of the dividers in A , transfer the distances A , 10 ; A , 20 ; & c ...
... perpendicular to AB and produce it to F ; draw BE parallel to CF and join AD . Divide the arc AD into nine equal parts as A , 10 ; 10 , 20 ; & c . and with one foot of the dividers in A , transfer the distances A , 10 ; A , 20 ; & c ...
Página 47
... perpendicular to AB , then ABC is the triangle required . AB , measured by the same scale of equal parts , will be 288 , and BC will be 384 . By Calculation . As sine of B 90 ° Is to sine of A 53 ° 8 ' · 10.00000 9.90311 So is AC 480 ...
... perpendicular to AB , then ABC is the triangle required . AB , measured by the same scale of equal parts , will be 288 , and BC will be 384 . By Calculation . As sine of B 90 ° Is to sine of A 53 ° 8 ' · 10.00000 9.90311 So is AC 480 ...
Página 48
... perpendicular BC . Extend the compasses , on the line of sines , from 90 ° to 36 ° 52 ' , the complement of the ... perpendicular BC and hypothenuse AC . Ans . BC = 82 and AC 98 . - 5. In the right - angled triangle ABC , are given the ...
... perpendicular BC . Extend the compasses , on the line of sines , from 90 ° to 36 ° 52 ' , the complement of the ... perpendicular BC and hypothenuse AC . Ans . BC = 82 and AC 98 . - 5. In the right - angled triangle ABC , are given the ...
Página 52
... perpendicular BC . Ans . A = 31 ° 28 ′ , C = 58 ° 32 ′ and BC = 142 . 6. In a right angled triangle ABC , the hypothenuse AC is 150 and one side BC 69 ; required the angles and other side . Ans . C = 62 ° 37 ′ , A = 27 ° 23 ′ and AB ...
... perpendicular BC . Ans . A = 31 ° 28 ′ , C = 58 ° 32 ′ and BC = 142 . 6. In a right angled triangle ABC , the hypothenuse AC is 150 and one side BC 69 ; required the angles and other side . Ans . C = 62 ° 37 ′ , A = 27 ° 23 ′ and AB ...
Página 53
... perpendicular to CF , and therefore CF being radius , EC , CG are the tangents of the angles EFC , CFG ; it is also evident that EB is the sum of the sides BA , AC , and that BF is the difference ; therefore since BC , FG are parellel ...
... perpendicular to CF , and therefore CF being radius , EC , CG are the tangents of the angles EFC , CFG ; it is also evident that EB is the sum of the sides BA , AC , and that BF is the difference ; therefore since BC , FG are parellel ...
Términos y frases comunes
ABCD ABFD acres adjacent adjacent angles angle ABC angle opposite angled triangle base bearing and distance breadth Calculation centre Co-secant Secant Co-sine Co-tang column cube root decimal DEMONSTRATION departure corresponding diff difference of latitude Dist divide division line draw equal EXAMPLES feet figures find the angle find the area four-pole chains fourth term given angle given area given bearing given number given ratio given side John Gummere Lat Dep latitude and departure length logarithm M.
M. Sine measured meridian distance natural number off-sets parallel parallelogram perches perpendicular quired quotient radius rectangle remainder Required the area right angle right line right-angled triangle RULE semiperimeter side AB side AC square root station stationary line subtract survey tance Tang tangent tract of land trapezium trapezoid triangle ABC trigonometry