A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Página 39
... radius being 10000000000 , and consequently its lo- garithm 10 . Let the radius CB , Fig . 32 , be supposed to consist of 10000000000 equal parts as above , and let the qua- drant DB be divided into 5400 equal arcs , each of these will ...
... radius being 10000000000 , and consequently its lo- garithm 10 . Let the radius CB , Fig . 32 , be supposed to consist of 10000000000 equal parts as above , and let the qua- drant DB be divided into 5400 equal arcs , each of these will ...
Página 45
... radius . EXAMPLES . 1. In the triangle ABC , there are given the angle A = 32 ° 15 ' , the angle B = 114 ° 24 ' , and consequently the angle C = 33 ° 21 ' , and the side AB = 98 ; * required the sides AC and BC . By Construction , Fig ...
... radius . EXAMPLES . 1. In the triangle ABC , there are given the angle A = 32 ° 15 ' , the angle B = 114 ° 24 ' , and consequently the angle C = 33 ° 21 ' , and the side AB = 98 ; * required the sides AC and BC . By Construction , Fig ...
Página 53
... radius , EC , CG are the tangents of the angles EFC , CFG ; it is also evident that EB is the sum of the sides BA , AC , and that BF is the difference ; therefore since BC , FG are parellel EB : BF :: EC : CG ( 2.6 . ) : that is , the ...
... radius , EC , CG are the tangents of the angles EFC , CFG ; it is also evident that EB is the sum of the sides BA , AC , and that BF is the difference ; therefore since BC , FG are parellel EB : BF :: EC : CG ( 2.6 . ) : that is , the ...
Página 56
... radius , describe a circle , meeting AC produced , in G and E , and AB in F. Then it is evident that AE is equal to the sum of the sides AC , BC , and that AG is equal to their difference ; also because CD bi- sects FB ( 3.3 ) , it is ...
... radius , describe a circle , meeting AC produced , in G and E , and AB in F. Then it is evident that AE is equal to the sum of the sides AC , BC , and that AG is equal to their difference ; also because CD bi- sects FB ( 3.3 ) , it is ...
Página 60
... radius FH , a circle be described , it will pass through the point G FE ( 31.3 ) . = AD + AD + DB 1 1 -- AD + AB- Now 2 AF 2 AD + 2 DF ACAB ; therefore AF AC + AB ; Also FK — } IK — † EH BC ; hence by adding equals to equals , AF + FK ...
... radius FH , a circle be described , it will pass through the point G FE ( 31.3 ) . = AD + AD + DB 1 1 -- AD + AB- Now 2 AF 2 AD + 2 DF ACAB ; therefore AF AC + AB ; Also FK — } IK — † EH BC ; hence by adding equals to equals , AF + FK ...
Términos y frases comunes
ABCD ABFD acres adjacent adjacent angles angle ABC angle opposite angled triangle base bearing and distance breadth Calculation centre Co-secant Secant Co-sine Co-tang column cube root decimal DEMONSTRATION departure corresponding diff difference of latitude Dist divide division line draw equal EXAMPLES feet figures find the angle find the area four-pole chains fourth term given angle given area given bearing given number given ratio given side John Gummere Lat Dep latitude and departure length logarithm M.
M. Sine measured meridian distance natural number off-sets parallel parallelogram perches perpendicular quired quotient radius rectangle remainder Required the area right angle right line right-angled triangle RULE semiperimeter side AB side AC square root station stationary line subtract survey tance Tang tangent tract of land trapezium trapezoid triangle ABC trigonometry