| Francis Lieber, Edward Wigglesworth, Thomas Gamaliel Bradford, Henry Vethake - 1832
...The three angles of a triangle ore together equal to two right angles; and in aright-angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the two sides. This last is still called the Pythagorean theorem (also magister matheteos),... | |
| Olinthus Gregory - 1834 - 427 páginas
...the rule to the respective case under which any specified example falls : and it will then be found, **since a right angle is always one of the data, that...are given, the third may be found by means of the** property in Plane Geom. Triangles, prop. 16. Hypoth. = v/(base' + perp.') Base= v/(hyp.a — perp.2)=... | |
| Olinthus Gregory - 1834 - 427 páginas
...the rule to the respective case under which any specified example falls : and it will then be found, **since a right angle is always one of the data, that...becomes simplified in its application. 2. When two of** th&.sides are given, the third may be found by means of the property in Plane Geom. Triangles, prop.... | |
| William Smyth - 1834 - 72 páginas
...third. This case, however, may be solved by means of the known property of a right angled triangle, viz. **the square of the hypothenuse is equal to the sum of the** squares of the two sides. It may moreover be resolved with facility by means of the two propositions... | |
| Abel Flint - 1835 - 334 páginas
...without finding the angles ; according to the following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, **THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE** SQUARES OF THE TWO LEGS. HENCE, THE SQUARE OF THE GIVEN LEG BEING SUBTRACTED FROM THE SQUARE OF THE... | |
| W H. Spiller - 1835 - 196 páginas
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as **the square of the hypothenuse is equal to the sum of the** squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
| Adrien Marie Legendre - 1836 - 359 páginas
...may be found by the first two theorems ; or if two of the sides are given, by means of the property, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. EXAMPLES. Ex. 1. In the right angled triangle BCA, there are given... | |
| 1837 - 249 páginas
...found by either of the four last cases : or, if two of the sides are given, by means of the property **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
| Alexander Jamieson - 1837 - 472 páginas
...the sides DH and CE ; that is, tf=\(xy). Consequently, by the property of the right angled triangle, **that the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular, we shall have (i,y =*• + «*—y)'; and by extracting the... | |
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