 | Robert Potts - 1868 - 434 páginas
...part of it produced, together with the square on half the line bisected, i3 equal to the square on the straight line which is made up of the half and the...line AB be bisected in C, and produced to the point />• Then the rectangle AD, DB, together with the square on CB, shall be equal to the square on CD.... | |
 | Woolwich roy. military acad - 1868 - 426 páginas
...part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced. 11. To describe a rectilineal figure which shall be similar to one given rectilineal figure and equal... | |
 | 1868 - 886 páginas
...part of it produced, together with the square of half the line bisected, is equal to the square of the straight line which is made up of the half and the part produced. 25 5. Divide a given straight line into two parts, so that the rectangle contained by the whole and... | |
 | Robert Johnston (F.R.G.S.) - 1869 - 196 páginas
...produced, and the part of it produced, together with the square of half the line bisected, is equal to the straight line which is made up of the half and the part produced. 4. The diameter is the greatest straight line in a circle ; and, of all others, that which is nearer... | |
 | Euclides - 1871 - 136 páginas
...part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the part produced. Iff M Q- JT Let the st. line AB be bisected in tfand produced to D. Then must rect. AD, DB together... | |
 | Benjamin Hallowell - 1872 - 286 páginas
...the part produced, with the square of half the line bisected, are together equal to the square of the line which is made up of the half and the part produced.* (Let AB be bisected in C, and produced to D ; D } then will AD x DB + CB2 = CD\ or CB2 x DB. Demonstration.... | |
 | Benjamin Hallowell - 1872 - 302 páginas
...the part produced, with the square of half the line bisected, are together equal to the square of the line which is made up of the half and the part produced.* f Let AB be bisected in C, and produced to D; D -5 then will AD x DB + CB' = CD\ or CB2 (=CD' — AD... | |
 | Henry Major - 1873 - 592 páginas
...CMG is equal to the rectangle AD, DB : add to each LG which is equal to the square of CB ; therefore the rectangle AD, DB, together with the square of CB, is equal to the gnomon CMG, and the figure LG; but the gnomon CMG and LG make up the whole figure CEFD, which is the... | |
 | Euclides - 1874 - 342 páginas
...part of it produced, together with the square on half the line bisected, is equal to the square on the straight line which is made up of the half and the...produced. Let the straight line AB be bisected in 0, and produced to the point 1). Then the rectangle AD, DB, together with the square on CB, shall be... | |
 | Euclid, James Bryce, David Munn (F.R.S.E.) - 1874 - 234 páginas
...produced, together with the square on half the line bisected, is equal to the square on the slraiyht line made up of the half and the part produced. Let the straight line AB be bisected in C and produced to D, the rectangle contained by |L the whole line AD, and the part DB, together with the square on CB,... | |
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