 | Daniel W. Fish - 1874 - 302 páginas
...What is the area of an isosceles triangle whose base is 20 ft., and each of its equal sides 15 feet 1 RULE. — From half the sum of the three sides, subtract each side teparately ; multiply the half -sum and the three remainders together; the square root of the product... | |
 | Daniel W. Fish - 1874 - 300 páginas
...What is the area of an isosceles triangle whose base is 20 ft., and each of its equal sides 15 feet ? RULE. — From half the sum of the three sides, subtract each side separately ; multiply the half-surn ami the three remainders together; the square root of the product... | |
 | Lorenzo Fairbanks - 1875 - 472 páginas
...perpendicular 18.25 chains ? PROBLEM III. 710. To find the area of a triangle when three sides are given. RULE. — From half the sum of the three sides subtract each side separately. Then multiply the half sum and the three remainders continually together, and the square... | |
 | Horatio Nelson Robinson - 1875 - 468 páginas
...of an isosceles triangle whose base is 20 ft., each of its equal sides 15 ft. ? Ans. 111.85 sq. ft. RULE, from half the sum of the three sides subtract each side separately ; multiply the half-sum and the three remainders together ; the square root of the product... | |
 | Henry Lewis (M.A.) - 1875 - 104 páginas
...CASE II. — The area of a triangle may, however, be determined from its three sides by the following rule: — From half the sum of the three sides, subtract each side separately; then multiply the half sum and the three remainders together, and the square root of the... | |
 | John Barter (of the science and art coll, Plymouth.) - 1877 - 328 páginas
...the journey is completed ? EXERCISE CCXV. Having the three sides of any triangle given, to find its area. Rule. — From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and the square root of the last... | |
 | Stoddard A. Felter, Samuel Ashbel Farrand - 1877 - 496 páginas
...= 9, 2d remainder. 27 — 24 = 3, 3d remainder. 27 X 15 X 9 X 3 = 10935. y 10935 = 104.57 sq. rds. area. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the continued product of these remainders by half the sum of the sides,... | |
 | William James Milne - 1877 - 402 páginas
...the product of the base by the altitude. When the three sides are given, the following is the rule: RULE. — From half the sum of the three sides subtract each side separately. Multiply together the half sum and the three remainders, and extract the square root of... | |
 | George Albert Wentworth - 1877 - 416 páginas
...figure. § 424 GEOMETRY. — BOOK V. EXERCISES. 1. The area of any triangle may be found as follows : From half the, sum of the three sides subtract each side severally, multiply together the half sum and the three remainders, and extract the square root of the product.... | |
 | Samuel Mecutchen, George Mornton Sayre - 1877 - 200 páginas
...preceding right triangle, AB is the hypotenuse, and AC, the perpendicular. To find the area of a triangle. RULE. From half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product... | |
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RULE. From half the sum of the three sides subtract each side severally. 
