 | John Bonnycastle - 1829 - 256 páginas
...102. 5/e. PROBLEM III. To find the area of a triangle whose three sides only are given. RULE.* . 1 . From half the sum of the three sides subtract each side severally. * Demon. Let AC— a, ±3=b, uc=c, and AD=a:; (See preceding fig.) Then, since BD=&— x, we shall... | |
 | James Hale - 1829 - 124 páginas
...Perpendicular. RULE 2. If the three Sides of a Triangle be given, its Area may be thus obtained: — From half the sum of the three Sides, subtract each Side severally, then extract the Square Root of the continued Product of the half sum and three remainder for the Area.... | |
 | Thomas Conkling (W.) - 1831 - 302 páginas
...three lines or sides. PROBLEM3. When the sides of a triangle are given, to find the content. . ' ' . RULE. From half the sum of the three sides, subtract each side severally; then, multiply that half sum and the three remainders together; and the sqipre root of the last product... | |
 | George Alfred - 1834 - 336 páginas
...14 acres 2 roods 32 poks PROBLEM 7. To find the area of a triangle when the three sides are given. RULE. From half the sum of the three sides subtract each side several! y, then multiply the half sum and the three remainders continually together, and the square... | |
 | Frederick Augustus Griffiths - 1840 - 436 páginas
....?i__ =140 Square yards. Area required. To find the Area of a Triangle, whose three Sides are given. From half the sum of the three sides, subtract each side severally ; multiply the half sum, and the three remainders together, and the square root of the product will... | |
 | Charles Waterhouse - 1842 - 180 páginas
...by means of the given proportion, the other sides may be found. PROB. IV. — To Measure a Triangle. RULE. — From half the sum of the three sides, subtract each side severally ; multiply these three remainders and the said half sum continually together ; the square root of the... | |
 | Charles Haynes Haswell - 1844 - 298 páginas
...cd, and half the product will be the area. To find the Area of a Triangle by the length of its sides. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the half sum and the \hree remainders continually together, and the square... | |
 | Charles WATERHOUSE - 1844 - 228 páginas
...ft.=192 ft., Ans. „ 3. To find the area of a triangle. RULE. — If the three sides only are given. — From half the sum of the three sides, subtract each side severally ; multiply these three remainders and the said half sum continually together ; and the square root... | |
 | William Templeton (engineer.) - 1845 - 210 páginas
...superficies. 7.7^ / /3 =206-34375 square feet, the area. When only the three sides of a triangle can be given, to find the area. Rule. — From half the sum of the three sides, subtract each side severally ; multiply the half sum and the three remainders together, and the square root of the product is equal... | |
 | William Watson (of Beverley.) - 1845 - 188 páginas
...chains. Ans. 3a. Or. 18p. PROBLEM 3. — To find the area of a triangle, when three sides are given. RULE. From half the sum of the three sides, subtract each side severally, multiply the lialf sum, and the three • These, and the following, should be laid down with a plotting... | |
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RULE. From half the sum of the three sides subtract each side severally. 
