 | Elias Loomis - 1859 - 372 páginas
...one of its sides multiplied by the square root of 3. MENSURATION OF SURFACES. 63 PROBLEM III. (87.) To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides into their per . pendicular distance. For demonstration, see Geometry, Prop. 7, B. IV.... | |
 | Josiah Lyman - 1862 - 92 páginas
...the field. SECOND METHOD. (S9.) BY TRAPEZOIDS AND TRIANGLES. For a Trapezoid, the rule is, Multiply the sum of the two parallel sides by the perpendicular distance between them. Half the product will be the area. For a Triangle, Multiply the base by the perpendicular height, and... | |
 | Charles Davies - 1863 - 346 páginas
...ABCD, having two of its sides, AB, DC, parallel. The perpendicular, CE, is called, the altitude. 393. To find the area of a trapezoid. Rule. — Multiply half the sum of the two parallel lines by the altitude, and the product will be the area. (Bk. IV., Prop. VII.) Examples. 1. Required... | |
 | Emerson Elbridge White, Henry Beadman Bryant - 1865 - 344 páginas
...QUADRILATERALS, PENTAGONS, &c. ART. 176- (1.) To find the area of any quadrilateral having two sides parallel. RULE. — Multiply half the sum of the two parallel sides by the altitude, or perpendicular distance between those sides, and the product will be the area. NOTE. —... | |
 | William John Macquorn Rankine - 1866 - 356 páginas
...by a pair of parallel straight lines, and a pair of straight lines not parallel). Multiply the half sum of the two parallel sides by the perpendicular distance between them. 3. Triangle. RULE A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
 | Edward Thomas Stevens - 1866 - 434 páginas
...which has only two of its opposite sides parallel, as ABD c. AE is the perpendicular. c K u To Jind the area of a trapezoid. RULE : — Multiply half the sum of the parallel sides by tho perpendicular distance between them ; the product is the area. DD THE CIRCLE.... | |
 | Gerardus Beekman Docharty - 1867 - 474 páginas
...and 25.69 chains respectively, to find the area. Ans. 61 acres, 2 roods nearly. PROBLEM VI. Tojind the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the altitude of the trapezoid. (Geom., BI, th. 29.) Or, Multiply the altitude by the distance between the... | |
 | Isaac Todhunter - 1869 - 312 páginas
...Thus we obtain the rule which will now be given. 161. To find the area of a trapezoid. RULE. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 162. Examples : (1) The two parallel sides of a trapezoid are... | |
 | Emerson Elbridge White - 1870 - 350 páginas
...altitude. 4. To find the area of any quadrilateral having two sides parallel, Multiply one half of the sum of the two parallel sides by the perpendicular distance between tiiem. 5. To find the circumference of a circle, 1. Multiply the diameter by 3.1416. Or, 2. Divide... | |
 | J Alfred Skertchly - 1873 - 184 páginas
...two of its sides parallel, such as OPWC, is called a trapezoid; and its area is found by multiplying half the sum of the two parallel sides by the perpendicular distance between them. Here the area of 0 PWC equals | (O P+CW) x O C. The ordinate OP denotes the initial velocity, and C... | |
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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
