 | Charles Davies - 1854 - 436 páginas
...Dividing equation (1) by equation (2), member by member, we have, JO™ »BB_OTjW_Wesi0g— : hence, The logarithm of the quotient of two numbers, is equal to the logarithm of the dividend diminished by the logarithm of the divisor. 5. Since the logarithm of 10... | |
 | Adrien Marie Legendre, Charles Davies - 1857 - 442 páginas
...equation (1) by equation (2), member by member, we have, , , Jf J/ 10m~" = .^or, m — n = log.r^: hence, The logarithm of the quotient of two numbers, is equal to the logarithm of the dividend diminished by the logarithm of the divisor. 5. Since the logarithm of 10... | |
 | James B. Dodd - 1859 - 368 páginas
...have y=nm (41), in which x-\-y is the logarithm of the product n m. Logarithm of a Quotient. (309.) The logarithm of the quotient of two numbers, is equal to the logarithm of the dividend minus the logarithm of the divisor. Dividing the Equation ax = n by the Equation... | |
 | Joseph Allen Galbraith - 1860 - 288 páginas
...By multiplication, ДГхЛГ =оnim therefore, log NX M = я + m = log N + log M. PROPoSITION II. The logarithm of the quotient of two numbers is equal to the difference of the logarithms of the numbers. By division. N — = an~m M therefore N log — = n - m = log N - log... | |
 | Joseph Allen Galbraith, Samuel Haughton - 1860 - 310 páginas
...= a'» By multiplication, NX M = a»*" therefore, log NX M = n + m = log N+ log M. PROPOSITION II. The logarithm of the quotient of two numbers is equal to the difference of the logarithms of the numbers. By diviaion. N — = a"~m M therefore N log — = n — m = log N —... | |
 | Paul Allen Towne - 1865 - 314 páginas
...numbers, J which is 5 + 4. 13S. Again, a* = M and a" = N M By dividing we have a** = — . That is, The logarithm of the quotient of two numbers is equal to the difference of their logarithms, Thus, the logarithm of 100000000000 is 11. The logarithm of 100000000 is 8. And the logarithm of quotient,... | |
 | Elias Loomis - 1868 - 386 páginas
...find the number corresponding to the resulting logarithm, and it will be the product required. 397. The logarithm of the quotient of two numbers is equal to the logarithm of the dividend diminished by that of the divisor. If we divide Eq. (1) by Eq. (2), member... | |
 | Daniel Barnard Hagar - 1873 - 278 páginas
...by the other, member by member, we have ax+'=mn, in which x+y is the logarithm of the product mn. 4. The logarithm of the quotient of two numbers is equal to the logarithm of the dividend diminished by that of the divisor. For, dividing the equation a? = m by the... | |
 | Aaron Schuyler - 1864 - 506 páginas
...75831.667. 5. Find the product of 85, .097, and .125. Ans. 1.03062. DIVISION BY LOGARITHMS. 16. Proposition. The logarithm of the quotient of two numbers is equal to the logarithm of the dividend minus the logarithm of the divisor. (" (1) 6-= yn; then, by def., log TO... | |
 | Aaron Schuyler - 1875 - 284 páginas
...75831.667. 5. Find the product of 85, .097, and .125. Ans. 1.03062. DIVISION BY LOGARITHMS. 16. Proposition. The logarithm of the quotient of two numbers is equal to the logarithm of the dividend minus the logarithm of the divisor. Г (1) b" = m; then, by def., log m =... | |
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The logarithm of the quotient of two numbers is equal to the logarithm of the dividend minus the logarithm of the divisor. 
