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" To bisect a given arc, that is, to divide it into two equal parts. Let ADB be the given arc : it is required to bisect it. "
Elements of Geometry: Containing the Principal Propositions in the First Six ... - Página 100
por Euclid - 1789 - 272 páginas
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 páginas
...equal to the base EF. [L 4. Wherefore, in equal circles &c. QED PROPOSITION 30. PROBLEM. To bisect a given arc, that is, to divide it into two equal...parts. Let ADB be the given arc : it is required to bisect it. Join AB ; bisect it at C ; [I. 10. n from the point C draw CD at right angles to AB meeting...
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 páginas
...equal to the base EF. [1. 4. Wherefore, in equal circles &c. QED PROPOSITION 30. PROBLEM. To bisect a given arc, that is, to divide it into two equal...parts. Let ADB be the given arc : it is required to bisect it. Join AB; bisect it at C ; [I. 10. D from the point C draw CD at right angles to AB meeting...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1868 - 410 páginas
...equal to the base EF. (I. 4.) Theiefore, in equal circles, &c. QED PROPOSITION XXX. PROBLEM. To bisect a given arc, that is, to divide it into two equal parts. Let ADB be the given arc: it is required to bisect it. D Join AB, and bisect it in C; (1. 10.) from the point C draw CD at right angles to AB....
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The Acting Teacher's and Student's in Training Guide and Text Book for ...

Henry Major - 1873
...they contain equal angles in the triangles BCK, EFL; therefore BC is equal to EF. XXX. — To bisect a given arc, that is, to divide it into two equal parts. Let ABD be the given arc. Join AB, and bisect it in C ; from C draw CD at right angles to AB. ^ Then the...
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The Elements of Euclid, containing the first six books, with a selection of ...

Euclides - 1874
...to the base EF (I. 4). Therefore, in equal circles, &c. QED PROPOSITION 30. — Problem. To bisect a given arc, that is, to divide it into two equal...parts. Let ADB be the given arc ; it is required to bisect it. Construction. Join AB, and bisect it in C (I. 10) ; from the point C draw CD at right angles...
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Pure mathematics, Volumen1

Edward Atkins - 1874
...EF (I. 4). BC = base Therefore, in equal circles, &c. QED Proposition 30. — Problem. I To bisect a given arc, that is, to divide it into two equal parts. i Let ADB be the given arc. It is required to bisect it. CONSTRUCTION. — Join AB, and bisect it in...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1876 - 403 páginas
...the base EF. (I. 4.) Therefore, in equal circles, &c. QED •a PROPOSITION XXX. PROBLEM. To liieet a given arc, that is, to divide it into two equal...parts. Let ADB be the given arc : it is required to bisect it. D Join AB, and bisect it in C; (I. 10.) from the point C draw CD at right angles to AB....
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Elements of geometry, based on Euclid, books i-iii

Edward Atkins - 1876 - 119 páginas
...base EF (I. 4). BC = b»so Therefore, in equal circles, &c. QED Proposition 30. — Problem. To bisect a given arc, that is, to divide it into two equal parts. Let ADB be the given arc. It ia required to bisect it. CONSTRUCTION. — Join AB, and bisect it in C (T. 10). Prom the point 0 draw...
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Examination Christmas,1875

Education Department,London - 1876
...саше base and on the ¿ame side of it must pass. 3. Define similar segments of circles. To bisect a given arc, that is, to divide it into two equal parts. !• ind the centre of a circle which bisects a given arc at right angles, and passes through one extremity...
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Modern geometry [ed.] with an appendix by W.B. Jack

Richard Wormell - 1876
...given, to describe the circle of which it is the segment. .. .. .. .. .. .. .. .. 132 30. To bisect a given arc ; that is, to divide it into two equal parts. . . . . 132 34. To cut off a segment from a given circle which shall contain an angle equal to a given...
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