 | Dennis M'Curdy - 1846 - 166 páginas
...QED . 5 Th. The base of a triangle is to the sum of both the sides, as the difference of the sides is to the difference of the segments of the base, made by a perpendicular falling upon it from the vertex, or to the sum of the segments, when the base must be produced to meet... | |
 | Euclides - 1846 - 292 páginas
...AB.AF + AD.AH=AC.AG. 100. Given the vertical angle, the difference of the sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex : construct the triangle. BOOK IV, DEFINITIONS. i. A RECTILINEAL figure is said to... | |
 | John Radford Young - 1848 - 300 páginas
...Given one side, the difference between the square of the other side, and the square of the base, and the difference of the segments of the base, made by a perpendicular from the vertical angle, of a plain triangle, to determine the triangle. Put a = the given sides 62... | |
 | Euclid, Thomas Tate - 1849 - 120 páginas
...the greatest angle ? 37. Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; to construct the triangle. THEOREMS. 1. If two circles cut each other, the straight... | |
 | John Radford Young - 1850 - 294 páginas
...Given one side, the difference between the square of the other side, and the square of the base, and the difference of the segments of the base, made by a perpendicular from the vertical angle, of a plain triangle, to determine the triangle. Put a = the given sides Z?2... | |
 | Sir Henry Edward Landor Thuillier - 1851 - 826 páginas
..." Sine of B : AC. CASE 4thi Having the three sides, to find any angle. RULE. As the longest side or base, is to the sum of the other two sides, so is...sides, to the difference of the segments of the base, formed by a perpendicular let fall from its opposite angle. Half the difference of the segments thus... | |
 | Horatio Nelson Robinson - 1851 - 96 páginas
...AC in E. Join EF ; produce AC to D,, and join DB & BE. AE is the difference of the sides, and AF is the difference of the segments of the base made by a perpendicular from C, The triangle AEF gives the following proportion : This proportion is the theorem, as will appear... | |
 | Oliver Byrne - 1852 - 604 páginas
...the whole triangle into two right-angled triangles ; it will be, As the base, or sum of the segments, Is to the sum of the other two sides ; So is the difference...sides, To the difference of the segments of the base. Then, half the difference of the segments being added to the half sum, or the half base, gives the... | |
 | John William Norie - 1852 - 844 páginas
...by Rule I. III. When the three Sides are given, to find the Angles. As the base, or greatest side, Is to the sum of the other two sides, So is the difference...of those sides, To the difference of the segments made by a perpendicular let fall from the greatest angle upon the base. Then half this difference added... | |
 | Andrew Duncan (Surveyor) - 1854 - 156 páginas
...required, call either side on which the perpendicular will fall from the opposite angle the base, then as the base is to the sum of the other two sides so...difference of those sides to the difference of the segments made by the perpendicular, then half that difference added to half the sum gives the greater, and substracted... | |
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Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base. 
