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" ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... "
The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ... - Página 81
por Robert Simson - 1804
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

Euclid, John Playfair - 1846 - 334 páginas
...ABC, DEF are equal, the straight lines drawn from their centres are equal : therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4. 1.) to the base EF : and because the angle at A is equal to the angle at D, the...
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The Elements of Euclid, the parts read in the University of Cambridge [book ...

Euclides - 1846 - 292 páginas
...ABC, DEF are equal, the straight lines drawn from their centres are equal : Therefore the two sides BG, GC are equal to the two EH, HF, and the angle at O is equal to the angle at H — therefore the base BC is equal to the base EF : And, because the angle...
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The first three books of Euclid's Elements of geometry, with theorems and ...

Euclid, Thomas Tate - 1849 - 120 páginas
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC' EHF at their centres, and BAC, EOF at their circumferences : The circumference BKC is equal to the circumference ELF. Join BC, EF; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: Therefore...
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The geometry, by T. S. Davies. Conic sections, by Stephen Fenwick

Royal Military Academy, Woolwich - 1853 - 400 páginas
...circumferences. Let ABC, DBF be equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumferences : the circumference BKC...equal to the circumference ELF. Join BC, EF : And because the circles ABC, DEF are equal (Hyp.), the straight lines drawn from their centres are equal...
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The synoptical Euclid; being the first four books of Euclid's Elements of ...

Euclides - 1853 - 146 páginas
...circumferences. Let ABC, DEF, be equal circles, having the equal angles BGC, EHF, at their centres, aud BAC, EDF, at their circumferences : the circumference BKC is equal to the circumference ELF. A KN Join BC, EF. And because the circles ABC, DEF, are equal, the straight lines drawn from their...
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The first six books of the Elements of Euclid, with numerous exercises

Euclides - 1853 - 176 páginas
...circumferences. LET abc, def be equal circles, and the equal angles bgc, ehf at their centres, and bac, edf at their circumferences. The circumference bkc is equal to the circumference e1f. Join bc, ef ; and because the circles abc, def, are equal, the straight lines drawn from their...
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Elements of Geometry: Containing the First Six Books of Euclid with a ...

John Playfair - 1855 - 334 páginas
...drawn from their centres are equal : therefore the two sides BG, GC, are equal to the two EH, EF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4. 1.) to the base EF: and because the angle at A is equal to the angle at D, the...
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Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J ...

Euclides - 1860 - 288 páginas
...drawn from their centres are equal ; therefore the two sides BG and GC are equal to the two EH and HF; and the angle at G is equal to the angle at H ; therefore the base BC is equal to the base EF (I. 4) ; and because the angle at A is equal to the angle at D, the...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1860 - 380 páginas
...are equal : (In. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (I. 4.) And because the angle at A is equal to...
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The school edition. Euclid's Elements of geometry, the first six books, by R ...

Euclides - 1864 - 448 páginas
...are equal : (ln. def. 1.) therefore the two sides BG, GC, are equal to the two EH, HF, each to each : and the angle at G is equal to the angle at H; (hyp.) therefore the base BCis equal to the base EF. (l. 4.) And because the angle at A is equal to...
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