| Royal Military Academy, Woolwich - 1853 - 400 páginas
...Wherefore, if a straight line, etc. QED PROPOSITION XI. PROB. To divide a given straight line into two **parts, so that the rectangle contained by the whole,...parts, shall be equal to the square of the other part.** Upon AB describe (46. i.) the square ABDC ; bisect (10. i.) AC in E, and join BE ; produce CA to F,... | |
| Royal Military Academy, Woolwich - 1853 - 474 páginas
...divide a line of 20 inches in length into two parts such that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part. Let** x = the greater part ; then 20 — x = the less part, and hence by the question we have x8 = 20 (20... | |
| Euclides - 1853 - 334 páginas
...line. It is required to divide it into two such parts, that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part.** On AB describe (i. 46) the square ACDB ; and supposing A to be that extremity of AB adjacent to which... | |
| William Walton, Charles Frederick Mackenzie - 1854 - 266 páginas
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part.** Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
| Cambridge univ, exam. papers - 1854 - 282 páginas
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part.** Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
| William Somerville Orr - 1854 - 532 páginas
...divide a given straight line (AB) into two parts, so that the rectangle contained by the whole, and от **of the parts, shall be equal to the square of the other part.** From A draw AC perpendicular and equal to AB;* bisect AC in E,t and draw BE. Prolong С A to F, making... | |
| Robert Potts - 1855 - 1050 páginas
...parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line into two **parts, so that the rectangle contained by the whole,...parts, shall be equal to the square of the other part** Solve the same problem algebraically, and give the geometrical interpretation of the result. 4. The... | |
| Great Britain. Committee on Education - 1855 - 976 páginas
...of it, the angle contained by those two sides is a right angle. 3. Divide a straight line into two **parts, so that the rectangle contained by the whole...parts shall be equal to the square of the other part.** Section 3. 1. The angles in the same segment of a circle are equal. 2. If from a point without a circle... | |
| Euclides - 1855 - 262 páginas
...the square oflhe other part. Let AB be the given straight line. It is required to divide AB into two **parts, so that the rectangle contained by the whole and one of** tLe parts, shall be equal to the square of the other part. Upon AB describe (I. 46) the square СB.... | |
| Cambridge univ, exam. papers - 1856 - 200 páginas
...parts are together equal to the square of the whole line. 7. To divide a given straight line into two **parts, so that the rectangle contained by the whole...parts shall be equal to the square of the other part.** 8. If a straight line drawn through the centre of a circle bisect a straight line in it, which does... | |
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