 | Webster Wells - 1887 - 196 páginas
...remaining two the opposite parts. Then Napier's rules are : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product cf the cosines of the opposite parts. 146. Napier's rules may be proved by... | |
 | Webster Wells - 1887 - 200 páginas
...opposite parts. Then Napier's rules are : I. ТЫ sine of the middle part is equal to the product of t/ie tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 146. Napier's rules may be proved by... | |
 | Edwin Pliny Seaver - 1889 - 306 páginas
...со В are the opposite parts. These are Napier's rules: ( i ) The sine of a middle part is equal to the product of the tangents of the adjacent parts. (ii) The sine of a middle part is equal to the product of the cosines of the opposite parts* To prove these rules, let... | |
 | Edward Albert Bowser - 1892 - 392 páginas
...с are the adjacent parts, and a and со. B are the opposite parts. Then Napier's Rules are : (1) The sine of the middle part equals the product of the tangents of the adjacent parts. (2) The sine of the middle part equals the product of the cosines of the opposite parts. NOTE 1. —... | |
 | Edward Albert Bowser - 1894 - 206 páginas
...co. с are the adjacent parts, and a and co. B are the opposite parts. Then Napier's Rules are . (1) The sine of the middle part equals the product of the tangents of the adjacent parts. (2) The sine of the middle pan equals the product of the cosines of the opposite parts. NOTE 1. —... | |
 | Edward Albert Bowser - 1892 - 202 páginas
...are the adjacent parts, and a and со. B are the opposite parts. Then Napier's Rules are . (1) Tlie sine of the middle part equals the product of the tangents of the adjacent parts. (2) The sine of the middle part equals the product of the cosines of the opposite parts. NOTE 1. —... | |
 | Ephraim Miller - 1894 - 222 páginas
...comparison of Figs. 28 and 29 will show that Ntger's Rules apply in either case. 92. Napier's Rules. 1. The sine of the middle part equals the product of the tangents of the adjacent parts. 2. The sine of the middle part equals the product of the cosines of the opposite parts. 93. That Napier's... | |
 | Webster Wells - 1896 - 308 páginas
...remaining two the opposite parts. Then Napier's rules are : I. The sine of the middle part is equal to the product of the. tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. \ 142. Napier's rules may be proved by... | |
 | Andrew Wheeler Phillips, Wendell Melville Strong - 1898 - 362 páginas
...sin comp C=cos compjS cose. Napier's rules may be stated : I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to t he product of the cosines of the opposite parts. 84:. In the right spherical triangles... | |
 | Elmer Adelbert Lyman, Edwin Charles Goddard - 1900 - 228 páginas
...the adjacent parts, and 900 — c, 90 — A the opposite parts. Napier's Two Rules are as follows : The sine of the middle part equals the product of the tangents of the adjacent parts. The sine of the middle part equals the product of the cosines of the opposite parts. It will aid the... | |
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I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. The sine of the middle part is equal to the product of the cosines of the opposite parts. 
