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" ... figure, together with four right angles, are equal to twice as many right angles as the figure has be divided into as many triangles as the figure has sides, by drawing straight lines from a point F within the figure to each of its angles. "
The elements of plane geometry; or, The first six books of Euclid, ed. by W ... - Página 21
por Euclides - 1863
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Annual Report - Dept. of Education

Saskatchewan. Department of Education - 1906 - 188 páginas
...Corollary ? Show that all the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. (c) Derive the magnitude of an angle of a regular octagon. (d) If the exterior vertical angle of an...
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Hints to Travellers: Scientific and General, Volumen1

Royal Geographical Society (Great Britain) - 1906 - 514 páginas
...together with the line AB form an enclosed figure, then the sum of all the interior angles should be equal to twice as many right angles as the figure has sides, less four right angles. We thus have a check on the observed horizontal angles. It should be carefully...
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A School Geometry, Partes1-4

Henry Sinclair Hall - 1908 - 286 páginas
...GEOMETRY. COROLLARY 1. ^M <Ae interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Let ABCDE be a rectilineal figure of & sides. It is required to prove that all the interior angles...
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Intermediate Geometry: Being Sections V and VI of "geometry, Theoretical and ...

Walter Percy Workman - 1908 - 228 páginas
...angles ; and in any convex polygon the sum of the interior angles, together with four right angles, is equal to twice as many right angles as the figure has sides (Euc. I. 32, Cor.) 110 Congruence. CI — If two triangles have two sides and the included angle in...
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Introduction and books 1,2

Euclid - 1908 - 550 páginas
...somewhat simpler than, Simson's. 1. The sum of the interior angles of a convex rectilineal figure is equal to twice as many right angles as the figure has sides, less four. For let one angular point A be joined to all the other angular points with which it is not...
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Practical Calculations for Engineers: For the Use of Engineering Students ...

Charles E. Larard, Henry A. Golding - 1909 - 554 páginas
...angles. = 180' (fig. 2). FIG. 1. FIG. 2. The sum of the interior angles of any rectilineal figure is equal to twice as many right angles as the figure has sides, less 4. Thus, for example, in the irregular pentagon (fig. 3), = 2 x 5 x 90° - 4 x 90° ; FIG. 3....
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College Entrance Examination Papers in Plane Geometry

1911 - 192 páginas
...whose altitude is 3 inches. SEPTEMBER, 1909 1. The sum of all the interior angles of any polygon is equal to twice as many right angles as the figure has sides, less four right angles. 2. The angle between two chords which intersect within a circle is measured...
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Special Reports on Educational Subjects, Volúmenes26-27

Great Britain. Board of Education - 1912 - 1044 páginas
...half BC. 2. Prove that the interior angles of any rectilinear figure together with four right angles are equal to twice as many right angles as the figure has sides. Find the number of sides of a regular polygon, each angle of which is equal to the sum of an angle...
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The Teaching of Mathematics in the United Kingdom

Great Britain. Board of Education - 1912 - 632 páginas
...half BC. 2. Prove that the interior angles of any rectilinear figure together with four right angles are equal to twice as many right angles as the figure has sides. Find the number of sides of a regular polygon, each angle of which is equal to the sum of an angle...
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Annual Report of the Department of Education of ..., Volumen4,Parte1911;Volumen6

Alberta. Department of Education - 1912 - 244 páginas
...28—1. 6 8. Prove that all the interior angles of any rectilineal figure together with four right angles are equal to twice as many right angles as the figure has sides. 8 9. (a) If a straight line be bisected and produced to any point, the rectangle contained by the whole...
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