| 1885
...propositions, which are apparently quite unrelated to it. Thus the famous property of a right-angled triangle, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides, may be readily deduced from certain general properties of triangles... | |
| Francis Campin - 1881 - 249 páginas
...members through which they pass in coming on to it. From a property of the right-angled triangle, viz. **that the square of the hypothenuse is equal to the sum of the** squares of the sides enclosing the right angle, an expression is found which will give the thrust at... | |
| Alexis Claude Clairaut - 1881
...hypothenuse of the right-angled triangle, we readily discover that famous property of right-angled triangles **that the square of the hypothenuse is equal to the sum of the** squares on the two other sides. 19. If, then, of two squares, HDLK and AB c D, we desired to make one... | |
| Francis Campin - 1881 - 249 páginas
...members through which they pass in coining on to it. From a property of the right-angled triangle, viz. **that the square of the hypothenuse is equal to the sum of the** squares of the sides enclosing the right angle, an expression is found which will give the thrust at... | |
| Charles Scott Venable - 1881 - 366 páginas
...the other two : for the three figures are proportional to the squares of their homologous sides ; but **the square of the hypothenuse is equal to the sum of the** squares of the other two sides ; therefore, etc. * PROPOSITION XXX. THEOREM. The segments of two chords,... | |
| Henry Bartlett Maglathlin - 1882 - 368 páginas
...the side perpendicular to the base. A Right-angled Triangle. 388. It will be seen from the diagram **that The square of the hypothenuse is equal to the sum of the** squares of the other two sides. Hence, 389. To find the hypothenuse, Take the square root of the sum... | |
| Henry Griffith - 1882 - 171 páginas
...that the radii of a circle are equal, a fact of adjustment from outside ? In a rightangled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the sides. Are we to look at that, as the result of design ? Kepler's law, that the planets... | |
| Thomas Box - 1883 - 525 páginas
...sides = 1 • 0 and £ respectively ; then by the well-known rule for right-angled triangles, namely, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides, we have f, = J (a* — c2), which in our case becomes (I2 — i2) v/... | |
| Thomas Box - 1883 - 525 páginas
...sides = 1 • 0 and i respectively ; then by the well-known rule for right-angled triangles, namely, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides, wo have f,= A/ (a2 — c2), which in our case becomes (I2 — £2)v/... | |
| William Allen Sylvester - 1883 - 210 páginas
...having three sides and three angles, one of which is a right angle. In every right-angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular. Base. Given the base and perpendicular, to find the hypothenuse.... | |
| |