| William Smyth - 1834 - 72 páginas
...third. This case, however, may be solved by means of the known property of a right angled triangle, viz. **the square of the hypothenuse is equal to the sum of the** squares of the two sides. It may moreover be resolved with facility by means of the two propositions... | |
| Abel Flint - 1835 - 334 páginas
...without finding the angles ; according to the following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, **THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE** SQUARES OF THE TWO LEGS. HENCE, THE SQUARE OF THE GIVEN LEG BEING SUBTRACTED FROM THE SQUARE OF THE... | |
| W H. Spiller - 1835 - 196 páginas
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as **the square of the hypothenuse is equal to the sum of the** squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
| Adrien Marie Legendre - 1836 - 359 páginas
...may be found by the first two theorems ; or if two of the sides are given, by means of the property, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. EXAMPLES. Ex. 1. In the right angled triangle BCA, there are given... | |
| Alexander Jamieson - 1837 - 472 páginas
...the sides DH and CE ; that is, tf=\(xy). Consequently, by the property of the right angled triangle, **that the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular, we shall have (i,y =*• + «*—y)'; and by extracting the... | |
| 1837 - 249 páginas
...found by either of the four last cases : or, if two of the sides are given, by means of the property **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
| Charles Guilford Burnham - 1837 - 256 páginas
...the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, **the square of the hypothenuse is equal to the sum of the** squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
| Madras literary society - 1837
...which AE is the other kg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, **the square of the hypothenuse is equal to the sum of the** squares of the other two sides; in the right angle triangle AEB,— BE8 -f- AE JL AB* : but as BE,... | |
| Charles William Hackley - 1838 - 307 páginas
...last, and a very simple formula depending upon the well known property of the right angled triangle, **that the square of the hypothenuse is equal to the sum of the** squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
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