| Charles Reiner - 1837 - 254 páginas
...and if the equal angles be subtracted from these equals, the remaining angles must be equal. M.—If **two triangles have two angles of the one equal to two angles of the other, each to each,** what may be said of the remaining third angles ? P.—They must be equal,—for the reason alleged... | |
| William Whewell - 1837 - 226 páginas
...angle; therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the **triangles have two angles of the one equal to two angles of the other** ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
| Euclid, James Thomson - 1837 - 410 páginas
...is equal (const.) to FBD, and that the right angles BED, BFD are equal, the two triangles EBD, FBD **have two angles of the one equal to two angles of the other,** and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| Andrew Bell - 1837 - 290 páginas
...by BD ; and because the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD, **have two angles of the one equal to two angles of the other** ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| A. Bell - 1837 - 180 páginas
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore **two angles of the one equal to two angles of the other,** and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
| Euclides - 1838 - 264 páginas
...that the <UAx. right angle BED is equalt to the right angle BFD ; therefore the two triangles EBD, FBD **have two angles of the one equal to two angles of , the other, each to each ; and** the side BD, B Tf C •which is opposite to one of the equal angles in each, is common to both ; therefore... | |
| Robert Simson - 1838 - 434 páginas
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD **have two angles of the one equal to two angles of the other,** and the side BD, which is opposite to one of the equal angles in each is common to both ; therefore... | |
| Thomas Kerigan - 1838 - 804 páginas
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, **two angles of the one equal to two angles of the other,** viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
| Euclides - 1841 - 378 páginas
...* 15. 1. angle EBC: and the angle AEG is equal* to the angle BEH; therefore the triangles AEG, BEH **have two angles of the one equal to two angles of the other, each to each, and** the sides AE, EB, adjacent to the equal angles, equal to one another: therefore their other * 28. 1.... | |
| Chambers W. and R., ltd - 1842 - 744 páginas
...proposition gives still further information on this useful subject. It shows that if two triangle* **have two angles of the one equal to two angles of the other, each to each, and one side equal to one** aide, namely, either the sides adjacent to the equal angles, or the sides opposite to the equal angles... | |
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