 | T S. Taylor - 1880 - 152 páginas
...; then the bases shall be equal. (Assumed here as an axiom proved on page 70.) General Enunciation. To bisect a given finite straight line— that is, to divide it into two equal parts. Particular Enunciation. Given. — The finite straight AR line A B. — — ^— — — — Required.... | |
 | Isaac Todhunter - 1880 - 426 páginas
...rectangle contained by the whole and one of the parts may be equal to the square on the other part. Let AB be the given straight line : it is required to divide it into two parts, so that the rectangle contained by the whole and one of the parts may be equal to the square... | |
 | Elias Loomis - 1880 - 456 páginas
...such that the greater part may be a mean proportional between the whole line and the other part. E Let AB be the given straight line ; it is ••••'" '; required to divide it into two parts at the / point F, such that AB : AF : : AF : FB. At the extremity of the line AB erect the perpendicular... | |
 | Isaac Todhunter - 1880 - 208 páginas
...TQ is greater than TE, by L 19 ; therefore the square on PQ is greater than the square on HE; 504. Let AB be the given straight line ; it is required to divide it at C, so that the squares on AB and BC may be equal to twice the square on AC. We require then that... | |
 | Euclides, Frederick Burn Harvey - 1880 - 178 páginas
...prove that A ^ bisects the angle CBE. PROP. X. PROBLEM. To bisect a given finite straight line, ie to divide it into two equal parts. Let AB be the given finite straight line : It is required to bisect it. CONSTRUCTION. — 1. On AB construct an equilateral... | |
 | Pupil teachers - 1880 - 1516 páginas
...eI @ Ⅰea 口 donep 孔 丁 Ⅰmay ㎏ ⅠWice 山 esqu 打 ０0Ⅰ 山 e Ⅱ ole 丁 p 打 t ・ Let AB be the given straight line. It is required to divide AB into two parts, so that the rectangle contained by the whole line and one part, shall be equal to... | |
 | Euclides - 1881 - 236 páginas
...angle into thrte equal parts, that is, to triseot an angle, is beyond the power of elementary geometry, PROP. X. PROBLEM. To bisect a given finite straight...required to divide it into two equal parts. Describe upon AB (I. 1) an equilateral triangle AB C, and bisect (I. 9) the angle ACS by the straight line CD,... | |
 | George Albert Wentworth - 1881 - 266 páginas
...of the less. ON CONSTRUCTIONS. PROPOSITION XXI. PROBLEM. 302. To divide a given straight line into equal parts. Let AB be the given straight line. It is required to divide AB into equal parts. From A draw the indefinite line A 0. Take any convenient length, and apply it... | |
 | Marianne Nops - 1882 - 278 páginas
...rectangle contained by the whole and one of the parts may be equal to the square on the other part. Let AT? be the given straight line — It is required to divide it into two parts, so that the rect. contained by the whole and one of the parts = the sq. on the other. On AB... | |
 | George Albert Wentworth - 1882 - 268 páginas
...PROPOSITION XXI. PROBLEM. 302. To divide a given straight line into equal parts. A^-, ' — : , ,B ---. Let AB be the given straight line. It is required to divide AB into equal parts. Prom A draw the indefinite lino A 0. Take any convenient length, and apply it... | |
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To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts. 
