 | John Bascombe Lock - 1896 - 242 páginas
...pro. duce8' log«, 100 = 2. 120. The use of logarithms is based upon the following propositions : I. The logarithm of the product of two numbers is equal to the logarithm of one of the numbers plus the logarithm of the other. For, let logj m = x ; then m = bx,... | |
 | Andrew Wheeler Phillips, Wendell Melville Strong - 1898 - 362 páginas
...of the number m is the number .r which satisfies the equation, ax = 1n. This is written x = loga m. The logarithm of the product of two numbers is equal to the sum of the logarithms of the numbers. Thus loga;//я = logaw + logeя. The logarithm of the quotient of two numbers is equal to the logarithm... | |
 | George Albert Wentworth - 1898 - 424 páginas
...13. 0.42184*. 20. 0.04165 A . 655. Since a quotient is equal to the dividend divided by the divisor, The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor (§ 108). 656. Example. Divide 905.6 by 38.45. SOLUTION. log 905.6... | |
 | James William Nicholson - 1898 - 204 páginas
...(g), ab = 10»+''. ... (Art. 1), log (06) = a' + b', or by (A), log (ab) = log a + log b. 7 3. Il. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. For, Art. 2, (/) .>. (g), ? = 10«'-''. .•. (Art. 1), log( -... | |
 | George Albert Wentworth - 1898 - 424 páginas
...14. 0.02187s. 21. 4,516,298*. 655. Since a quotient is equal to the dividend divided by the divisor, The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor (§ 108). 656. Example. Divide 905.6 by 38.45. SOLUTION. log 905.6... | |
 | George Albert Wentworth - 1898 - 424 páginas
...14. 0.02187*. 21. 4,516)298I\ 655. Since a quotient is equal to the dividend divided by the divisor, The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor (§ 108). 656. Example. Divide 905.6 by 38.45. SOLUTION. log 905.6... | |
 | George Egbert Fisher - 1899 - 506 páginas
...2048 to the base 2 ? Since 2048 = 32 • 64, we have log, 2048 = Iog2 32 + logj 64 = 5 + 6 = 11. 16. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor; or, log(, (m -r- /;) = logj, m — logs n. Let logi m = x and logj... | |
 | James Morford Taylor - 1900 - 504 páginas
...Proof. Let M=ax, N=a!>; then M x N= ax+». § 346 Hence loge(3f y, N) = x + y = loga M -\- log. N. 442. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. Proof. Let M=a', N=a'; then M-*-N=a"'. §346 Hence log. (M •+•... | |
 | George Egbert Fisher, Isaac Joachim Schwatt - 1900 - 484 páginas
...rithm of 2048 to the base 2 ? Since 2048 = 32-64, we have loga 2048 = log232 + log264 = 5 + 6 = 11 7. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor; or, Iog6 (m -=- я) = logi, m - logi, л. Let logb m = x and logb... | |
 | George Egbert Fisher, Isaac Joachim Schwatt - 1901 - 646 páginas
...of 2048 to the base 2 ? Since 2048 = 32-64, we have log, 2048 = log, 32 + log, 64 = 5 + 6 = 11. 16. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor; or, log» (m -i- n) = logt 14 — logu "• Let log» m = x and... | |
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The logarithm of the product of two numbers is equal to the sum of the logarithms of the numbers. log» MN = log» M + log 
