 | George Egbert Fisher - 1901
...logarithm of 2048 to the base 2 ? Since 2048 = 32-64, we have log¡ 2048 = log232 + log2 64 = 5 + 6 = 11 7. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor; or, Iog6 (m -s- я) = log,, m - log,, я. Let log5 m = x and logb... | |
 | Louis Parker Jocelyn - 1902 - 445 páginas
...and n = a" ; 3. and mn = ax • ay = az+v. 4. .-. loga mn = x + y = loga m + loga n. 468. Prop. 4. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. 977 Dem. Let -- be the given quotient, m being the dividend 7Î-... | |
 | University of Sydney - 1904
...respectively equal to a, b and c, prove that — — -^=«. ao 10. Define a logarithm and prove that the logarithm of the product of two numbers is equal to the sum of their logarithms. Find the value of = • — . (3-721)"tf Given log 8-4=-9243, log 6'72='8274, log... | |
 | 1906
...it was not often taken. C. In TRIGONOMETRY the work was on the whole fairly good. Q. 33. Explain why the logarithm of the product of two numbers is * equal to the sum of the logarithms of the numbers. By means of logarithms given below, find the fifth root, and the fifth power of 0'69889 correct to... | |
 | George Albert Wentworth - 1906 - 421 páginas
...is evident that : The logarithm of a product is equal to the sum of the logarithms of the factors. The logarithm of a quotient is equal to the logarithm of the dividend less that of the divisor. The logarithm of a power of a number is equal to the logarithm of the number... | |
 | Frederick Howland Somerville - 1908 - 407 páginas
...(1) and (2), x = log m and y = log n. (Art. 438) Substituting in (3), log mn = log m + log n. 454. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. Let 10* = m (1) and 10» = n. (2) Dividing (1) by (2), jg = m.... | |
 | William Henry Metzler, Edward Drake Roe, Warren Gardner Bullard - 1908 - 341 páginas
...sum of the logarithms of its factors. Again, Therefore, loga ( — =xy = \ogam — loga n, n that is, the logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. Thus Iog105 = Iog10 10 - log]02 = 1.0000 - 0.3010 = 0.6970. Raising... | |
 | Earle Raymond Hedrick - 1908 - 421 páginas
...logarithm of a product is equal to the sum of the logarithms of the factors, for 10ra x 10" = 10"'+n. II. The. logarithm of a quotient is equal to the logarithm of the dividend less that of the divisor, for 10m -=- 10" = 10m~". III. The logarithm of a power of a number is equal... | |
 | Henry Lewis Rietz, Arthur Robert Crathorne - 1909 - 261 páginas
...: logio 255 = logi0 3 + Iogi0 5 + Iogi0 17. BASE NUMBER 04 LOGARITHM 2 10 125 3 i 2 A 3 i 32 -5 2. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. As above, let lognм = x and lognv = y, then, a* = u, ay = v, and... | |
 | Levi Leonard Conant - 1909 - 222 páginas
...numbers, and let x and y be their logarithms respectively. Then .'. log(ran) = x + y = log m + log n. 3. The logarithm of a quotient is equal to the logarithm of the dividend minus the logarithm of the divisor. PROOF. n .-.tog 2n = log m — log n. 4. The logarithm of any power... | |
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