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" The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES. "
A Text-book of Euclid's Elements for the Use of Schools. Books I.-VI. and XI - Página 79
por Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 456 páginas
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1876 - 446 páginas
...the middle points of AB andD C shall divide the quadrilateral into two equal parts. 8. The straight line, which joins the middle points of two sides of a triangle, is parallel to the base. 9. If a straight line be divided into any two parts, the square on the whole line is equal to...
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Elements of Geometry with Exercises for Students: An an Introduction to ...

Aaron Schuyler - 1876 - 384 páginas
...AE = EC; hence, DE bisects AC. GEOMETRY.— BOOK I. 104. Corollaries. 1. Tlie straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to its half. (?) 2. The straight line drawn from the middle point of one of the non-parallel...
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Syllabus of Plane Geometry: (corresponding to Euclid, Books I-VI) ...

Association for the improvement of geometrical teaching - 1876 - 66 páginas
...parallel to the base passes through the middle point of the other side. COR. 2. The straight line joining the middle points of two sides of a triangle is parallel to the base. [Cor. i. and Rule of Identity.] SECTION 4. PROBLEMS. PROB. i. To bisect a given angle. PROB....
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Exercises on Euclid and in Modern Geometry

James McDowell - 1878 - 310 páginas
...D have been each proved equal to EC, therefore FH and 11 D are equal. 4. The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it. In the Cor. to the last proposition it is proved that the straight line EH...
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Elements of Geometry: And the First Principles of Modern Geometry

William Henry Harrison Phillips - 1878 - 236 páginas
...straight line, it follows, that if AD = DB, and AE = EC, then DE || BC ; that is, the line joining the middle points of two sides of a triangle is parallel to the third D/. side. COR. 2, Since DE = BF = FC, DE = ^ that is, the line joining the middle, points of two sides...
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Elementary Geometry ...

James Maurice Wilson - 1878 - 450 páginas
...parallel to the base passes through the middle point of the other side. COR. 2. The straight line joining the middle points of two sides of a triangle is parallel to the base. EXERCISES FOR SOLUTION. i. If ABC is an isosceles triangle and A is double of either B or C,...
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The solution of geometrical exercises, explained and illustrated; with a ...

Charles Mansford - 1879 - 112 páginas
...enable us to write the proof in the usual form. The following may stand as an example : — The straight line which joins the middle points of two sides of a triangle is equal to half the third side. Particular Enunciation. — Let D and E be the middle points of the sides...
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Euclid, books i. & ii., with notes, examples, and explanations, by a late ...

Euclides - 1879 - 146 páginas
...line which joins the middle points of two sides of a triangle is parallel to the base. 3. The straight line which joins the middle points of two sides of a triangle is equal to half the base. 4. Given the middle points of the sides of a triangle, to construct it. 5....
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Elements of Geometry, After Legendre, with a Selection of Geometrical ...

Charles Scott Venable - 1881 - 380 páginas
...triangle is double the corresponding side of the given triangle. 25. (Corollary of 24. ) The straight line which joins the middle points of two sides of a triangle is parallel to the third side and equal to the half of it. And, conversely, if, through the middle point, D, of the side, AB, of...
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The Competitor, Volúmenes1-2

1882 - 486 páginas
...That is, AC is bisected in N. NOTE. — MN is equal to half of AB. Hence the straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to its half, Draw MP,LR, parallel to AF, and join ML, PR. Then from the property of the triangle...
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