| Charles Davies - 1842 - 368 páginas
...-ii 2 -1c=5a 2 i e ; for, ..... 7abx5a?-bc=35aWc. 50. Hence, for the division of monomials, we have the following RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor. II. Write in the quotient, after the co-efficient, all the letters common to the dividend and divisor,... | |
| Charles Davies - 1842 - 284 páginas
...= 5a3-162 tab for, 7a6 x 5a26c = 35a362c. Again, 8a36c Hence, for the division of monomials we have the following RULE. I. Divide the coefficient of the dividend by the coefficient of the divisor. II. Write in the quotient, after the coefficient, all the letters common to the dividend and divisor,... | |
| Warren Colburn - 1844 - 280 páginas
...one of the parts ? Ana. 3 1 c ; because 2 a times 3 bc ia 6 ab c. Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the letters of the divisor from the dividend. 3. Divide 16a6c by 4. 4. " 12aJc by 3a.... | |
| William Scott - 1844 - 568 páginas
...„. , , Consequently, — «r~srr~ =7asc3. Whence, to divide one monomial quantity by another, Rule. Divide the coefficient of the dividend by the coefficient of the divisor ; the result is the coefficient of the quotient. To obtain the literal part of the quotient, 1st. "When... | |
| Davis Wasgatt Clark - 1844 - 394 páginas
...both are polynomials. CASE I. 106. In this case, the dividend and divisor are both monomials. RULE. 1. Divide the coefficient of the dividend by the coefficient of the divisor. 2. Reject the letters common to both dividend and divisor when they have the same exponent; but when... | |
| Ormsby MacKnight Mitchel - 1845 - 308 páginas
...since 3X4a2=12a2. Hence we perceive, generally, that to obtain the coefficient of the quotient, we must divide the coefficient of the dividend by the coefficient of the divisor. Thus 24o2, divided by 6a2, produces 4. 67. If the division is not possible, we indicate it by writing... | |
| Elias Loomis - 1846 - 376 páginas
...exponent of the dividend. (67.) Hence for the division of monomials, we have the following RULE. 1. Divide the coefficient of the dividend by the coefficient of the divisor. 2. Subtract the exponents of the letters in the divisor from the exponents of the same letters in the... | |
| Elias Loomis - 1846 - 380 páginas
...exponent of the dividend. (67.) Hence for the division of monomials, we have the following RULE. 1 . Divide the coefficient of the dividend by the coefficient of the divisor. 2. Subtract the exponents of the letters in the divisor from the exponents of the same letters in the... | |
| Davis Wasgatt Clark - 1846 - 374 páginas
...are polynomials. CASE I. 106. In this case, the dividend and divisor are both monomials. , . RULE. 1. Divide the coefficient of the dividend by the coefficient of the divisor. the same, subtract the exponent of the divisor from that of the dividend, and the remainder will be... | |
| Olinthus Gilbert Gregory - 1848 - 572 páginas
...equal to the difference of their squares. SECT. IV. D witton. 1. To divide one monomial by another, divide the coefficient of the dividend by the coefficient of the divisor for the coefficient of the quotient, and subjoin to it a fraction having for its numerator the letters... | |
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