 | John Bonnycastle - 1829 - 256 páginas
...trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24,... | |
 | John Nicholson (Civil engineer) - 1830 - 240 páginas
...when the square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the...between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
 | Edinburgh encyclopaedia - 1830 - 856 páginas
...quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities draw AE, CF at right... | |
 | John Bonnycastle - 1833 - 310 páginas
...trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between...them, and half the product will be the area. EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24, and perpendicular... | |
 | Ira Wanzer - 1831 - 408 páginas
...40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the pr«' duct will be the area. Ex. How many square feet are contained in a board which is 12 feet... | |
 | Zadock Thompson - 1832 - 186 páginas
...is the area ? Ans. 54.299 rods. 307. To find (he. area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the... | |
 | Zadock Thompson - 1832 - 186 páginas
...is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the... | |
 | Francis Walkingame - 1833 - 204 páginas
...half the product will be the area. D. Fig. 5. В DE + BF x AC That is, ! = the area. For a trapezoid. Multiply the sum of the two parallel sides by the...between them ; and half the product will be the area. (1) How many square yards of paving are in the trapezium, whose diagonal is 65 feet, and the perpendiculars... | |
 | Ireland commissioners of nat. educ - 1834 - 370 páginas
...required its area ? Ans. 700-99. PROBLEM XIII. To find the area of a Trapezoid RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.* 1. Let A BCD be a trapezoid, the side AB = r — -¡ i 40, D С =... | |
 | John Bonnycastle - 1835 - 308 páginas
...trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the perpendicular distance between...them, and half the product will be the area. EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24, and perpendicular... | |
| |
Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 
